Stirling engine involves: (1) isothermal heat addition → (2) isochoric heat removal → (3) isothermal heat removal → (4) isochoric heat addition. ngine uses one mole of ideal monatomic gas and operates between a hot and a cold reservoir at temperatures TH = 400 K and Tc = 300 K, an olume of V₁ = 1 L and V/₂ = 4 L. Calculate the heat removal/addition in part (2) of the cycle. elect one: a. Q = 1247 J Ob. Q 4611 J c. Q-3458 J d 1247 I
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Q: It's a thermodynamics question.
A: To derive:
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Q: Р d a Va TH Tc b 3V₂ V
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- Consider a gas that follows the equation of state NRT aN² 2 P V - bN V2 This is called van der Waals gas (a,b > 0). For temperatures T > Tc : monotonically decreasing function. Assume T > Tc and Cy = 3NR/2. = 8a p(V) is a 27Rb Consider an insulated box with volume V₁. The box was divided by a wall. One of the compartments had volume Vo at temperature To, which was filled with van der Waals gas of amount N. The other compartment was vacuum. The system was in equilibrium. (i) The wall was removed abruptly. The gas expanded and occupied the entire box. This process is called adiabatic free expansion. The temperature in the box is now T₁ in equilibrium. What is T₁ - To? (ii) The internal energy of the gas does not change by adiabatic free expansion. Why? (iii) Instead of the abrupt removal, the wall was moved through adiabatic and quasi-static process, and the gas expanded to the entire volume of the box. The temperature in the box is now T2 in equilibrium. What is T₂? (iv) Show T₁ > T₂,…The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio of specific heat at constant pressure to that at constant volume is (a) 7/5 (b) 8/7 (c) 5/7 (d) 9/7If one mole of a monoatomic gas of (y = 5/3) is mixed with one mole of diatomic gas, then the (y = 715) value of y for the mixture will be, (a) 1.5 (b) 1.54 (c) 1.4 (d) 1.45
- A 2.00 mol sample of an ideal diatomic gas at a pressure of 1.10 atm and temperature of 420 K undergoes a process in which its pressure increases linearly with temperature. The final temperature and pressure are 720 K and 1.70 atm . Fid the change in internal energy, work done by the gas, and heat added.Consider one mole of a simple ideal gas enclosed in a cylindrical piston with rigid impermeable adiabatic walls. The piston has a cross sectional area ofA = 0.10 m^2 and the cylinder enclosing the gas has a height of h = 1.0 cm. The gas inside the piston has a temperature T = 300.K. Recall that the internal energy for an ideal gas is U= n cV,mT, where cV,m= 1.5 R is the molar heat capacity for the ideal gas. Calculate the pressure and the internal energy of the ideal gas.I need help solving number 11. In question 1, they say U=(3/2)PV I found work on the gas as -3/2PV, so therefore Q should be 6/2PV but the answer key says 6PV.
- Consider the composite system, which is held at 298 K, shown in the following figure. Assuming ideal gas behavior, calculate the total pressure and the partial pressure of each component if the barriers separating the compartments are removed. Assume that the volume of the barriers is negligible. O O O O O O O O O O O O ©2019 Pearson Education, Inc. O O O He 2.00 L 1.50 bar boo Ne 3.00 L 2.50 bar Xe 1.00 L 1.00 barConsider the process shown in (Figure 1). Figure p (kPa) 400- EV 200- 100 200 300 0₁ 0 V (cm³) 1 of 1 How much work is done on the gas in this process? Express your answer with the appropriate units. W = Submit μA Value Provide Feedback Request Answer Units ?* ? 63. During isothermal compression, the internal energy of an ideal gas : a. Decreases b. Can go either way depending on the precise pressures and volumes c. Stays the same d. Increases 64. What is the total internal energy of a sample of 9 moles of air (considered as an ideal gas) at a temperature of 3°C? Assume that the rotational degrees of freedom are fully activated, and that the vibrational modes are "frozen out". (k=1.38 x 10-23 J/K, N-6.022x10²3) 3°C = 273+3 = 276 U= n NAF ( 1₂ KT) (9)(6.022 X 10²²) x 1.38×10²³ x 276) = 1032 a. 1.19 x 105 J b. 9.29 x 104 J c. 7.23 x 104 J d. 5.16 x 104 J 65. What is the average translational kinetic energy per oxygen molecule in this sample? a. 1.2 x 10-20 J b. 9.14 x 10-21 J c. 5.71 x 10-21 J d. 1.54 x 10-20 J 66. Is this kinetic energy the same or different from the nitrogen molecules in the sample? a. Different b. The same 67. What is the rms speed of the oxygen molecules in this sample? (the atomic mass number of oxygen is 15.994, 1 u =…
- Hello, Can I please have help regarding this problem ? Thanks. Suppose that the clock on our lecture room has a minute-hand length of 10 cm.(Use a coordinate system with the origin at center of clock and +x axis along the3PM direction and the +y direction along the 12PM direction). From the 12 to 8mark, for the tip of the minute hand:a) Sketch a vector diagram labeling ri, rf, Δr, Vi, Vf, and ΔV.b) Calculate the displacement vector in unit-vector notation.c) Calculate the average velocity vector in unit-vector notation.d) Calculate the average acceleration vector in unit-vector notation.e) Calculate magnitude and direction of the average acceleration vector.f) Calculate the magnitude and direction of the total acceleration of the tip ofthe minute hand at the 6 mark.One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 10^5 Pa undergoes a reversible adiabatic compression. At the end of the process, the pressure is 1.00 × 10^6 Pa. Calculate the final temperature of the gas. Calculate q, w, ΔU, and ΔH for this process.