Step The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 ÷ 3 = so x6 = (x2)3. Express each term as a perfect cube. 27d³64 33d³ - 26 3³d³- = (3d) ³ - (1 ])²)³ 1²
Step The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 ÷ 3 = so x6 = (x2)3. Express each term as a perfect cube. 27d³64 33d³ - 26 3³d³- = (3d) ³ - (1 ])²)³ 1²
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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