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Step 5 Substituting u = 7 – 6x² gives 4/3 2 4/3 (7- 6x |(7 - 6x3)3(-12x) dx = + C (7- 62) (7– 6z)/3 + C Step 6 To check the result, differentiate the antiderivative obtained in the previous step by using the Sum Rule of Differentiation. 4/3 6x + c 3 4 d 6x2 + d (C) 3 4 d Now use the Chain Rule and simplify. (-12x) 3 - (7 - (-12x) Submit Skip (you cannot come back)

Step 5 Substituting u = 7 – 6x² gives 4/3 2 4/3 (7- 6x |(7 - 6x3)3(-12x) dx = + C (7- 62) (7– 6z)/3 + C Step 6 To check the result, differentiate the antiderivative obtained in the previous step by using the Sum Rule of Differentiation. 4/3 6x + c 3 4 d 6x2 + d (C) 3 4 d Now use the Chain Rule and simplify. (-12x) 3 - (7 - (-12x) Submit Skip (you cannot come back)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 5 Substituting u = 7 – 6x2 gives 4/3 2 4/3 (7- 6xv (7 – 6x2)1/3(-12x) dx = + C (7-6) 3 (7-622)/3 + C Step 6 To check the result, differentiate the antiderivative obtained in the previous step by using the Sum Rule of Differentiation. 4/3 6x + c 3 4 d 6x + (C) 3 4 d Now use the Chain Rule and simplify. (-12x) 3 - (7 - (-12x) Submit Skip (you cannot come back)
Transcribed Image Text:Step 5 Substituting u = 7 – 6x2 gives 4/3 2 4/3 (7- 6xv (7 – 6x2)1/3(-12x) dx = + C (7-6) 3 (7-622)/3 + C Step 6 To check the result, differentiate the antiderivative obtained in the previous step by using the Sum Rule of Differentiation. 4/3 6x + c 3 4 d 6x + (C) 3 4 d Now use the Chain Rule and simplify. (-12x) 3 - (7 - (-12x) Submit Skip (you cannot come back)
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