Step 4 We now have u? = t? + tan(t) + C. Since u(0) = -9, we can substitute into the equation and solve for C = 81 81 Step 5 Noting that u(0) = -9 is negative, then when we solve for u we must get u = -9 Submit Skip (you cannot come back).
Step 4 We now have u? = t? + tan(t) + C. Since u(0) = -9, we can substitute into the equation and solve for C = 81 81 Step 5 Noting that u(0) = -9 is negative, then when we solve for u we must get u = -9 Submit Skip (you cannot come back).
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I just need help with step 5, thank you!

Transcribed Image Text:Step 4
We now have u² = t² + tan(t) + C.
Since u(0) = -9, we can substitute into the equation and solve for C = 81
81
Step 5
Noting that u(0) = -9 is negative, then when we solve for u we must get u =-9
Submit
Skip (you cannot come back)

Transcribed Image Text:Find the solution of the differential equation that satisfies the given initial condition.
du - 2t + sec2(t), u(0) = -9
dt
2u
Step 1
du
Separating
dt
2t + sec?(t) gives us 2u du = ( 2t + (sec(t))-|
dt.
2t + sec2 (t)
2u
Step 2
Ignoring the constant of integration, integrating the left side gives
2u du =
u?
Step 3
Ignoring the constant of integration, integrating the right side gives
(2t + sec?(t)) dt = 12 + tan (t)
t? + tan(t)
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