Step 4 Thus, we have P(0 sz s 3)-(3) - (0). From part (a), we have the cdf value (0) = 0.5, the area to the left of the mean z = μ = 0. Using Table A.3 in the appendix, the value of 0(3) is determined by finding the table entry marked 3.0 and the corresponding column marked .00. This gives us (3) = Use these cdf values to compute the probability, rounding your answer to four decimal places. P(0 ≤ Z ≤ 1) = (3) - (0) -0.5
Step 4 Thus, we have P(0 sz s 3)-(3) - (0). From part (a), we have the cdf value (0) = 0.5, the area to the left of the mean z = μ = 0. Using Table A.3 in the appendix, the value of 0(3) is determined by finding the table entry marked 3.0 and the corresponding column marked .00. This gives us (3) = Use these cdf values to compute the probability, rounding your answer to four decimal places. P(0 ≤ Z ≤ 1) = (3) - (0) -0.5
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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