Step 4 3 and t = -' 2 3 The last step in We have found that the critical numbers that are zeros of f'(t) are t = the Second Derivative test is to evaluate f"(c) for these critical numbers and simplify the results. 6 f"(t) 4/6 %3D f"(t) = 3 (-VA) 4/6 3

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 4
3
and t
3
The last step in
2
We have found that the critical numbers that are zeros of f'(t) are t = V
= -
the Second Derivative test is to evaluate f"(c) for these critical numbers and simplify the results.
6.
f"(t)
3
f"
3
3
f"(t)
m(-V) -
(-VE
%D
3
4/6
Transcribed Image Text:Step 4 3 and t 3 The last step in 2 We have found that the critical numbers that are zeros of f'(t) are t = V = - the Second Derivative test is to evaluate f"(c) for these critical numbers and simplify the results. 6. f"(t) 3 f" 3 3 f"(t) m(-V) - (-VE %D 3 4/6
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