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Step 3 We must also convert xõ dx into an expression involving u. Using du = 9x³ dx, then we get x dx = du. 9. Step 4 1 1 1 Now, if u = x°, then dx = 1 + x18 du. 1 + u² %3D 1 + 1 This evaluates as 9. du = 1 + u2 + C. Submit Skip (you cannot come back).

Step 3 We must also convert xõ dx into an expression involving u. Using du = 9x³ dx, then we get x dx = du. 9. Step 4 1 1 1 Now, if u = x°, then dx = 1 + x18 du. 1 + u² %3D 1 + 1 This evaluates as 9. du = 1 + u2 + C. Submit Skip (you cannot come back).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 3 We must also convert xõ dx into an expression involving u. Using du = 9x³ dx, then we get x dx = du. 9. Step 4 1 1 1 Now, if u = x°, then dx = 1 + x18 du. 1 + u² %3D 1 + 1 This evaluates as 9. du = 1 + u2 + C. Submit Skip (you cannot come back).
Transcribed Image Text:Step 3 We must also convert xõ dx into an expression involving u. Using du = 9x³ dx, then we get x dx = du. 9. Step 4 1 1 1 Now, if u = x°, then dx = 1 + x18 du. 1 + u² %3D 1 + 1 This evaluates as 9. du = 1 + u2 + C. Submit Skip (you cannot come back).
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