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Step 3 Thus, we have found P(E5) = 0.1. Now use this value to calculate P(E4) using the second equation. P(E4) = 2P(E5) = 20

Step 3 Thus, we have found P(E5) = 0.1. Now use this value to calculate P(E4) using the second equation. P(E4) = 2P(E5) = 20

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 3 Thus, we have found P(E5) = 0.1. Now use this value to calculate P(E4) using the second equation. P(E4) = 2P(E5) = 20 ||
Transcribed Image Text:Step 3 Thus, we have found P(E5) = 0.1. Now use this value to calculate P(E4) using the second equation. P(E4) = 2P(E5) = 20 ||
A sample space consists of five simple events with P(E₁) = P(E₂) = 0.3, P(E3) = 0.1, and P(E4) = 2P(E5). and E5. Find the probabilities for simple events E4 Step 1 Recall that the sum of the probabilities for all simple events in a sample space equals 1. Since there are five simple events, E₁, E₂, E3, E4, E5, this yields the following equation. P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5) = 1 We are given that P(E₁) = P(E₂) = 0.3 and P(E3) = 0.1. Substitute these values into the above equation and simplify. P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5) = 1 0.3 +0.3 + 0.1 0.7 P(E5) 0.1 + P(E4) + P(E5) = 1 = 0.7 + P(E4) + P(E5) = 1 Step 2 We have simplified P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5): = 1 to the equation P(EÂ) + P(E5) = 0.3. We are also given that P(E4) = 2P(E5). Note that both of these equations involve only P(E4) and P(E5). Substitute the second equation into the first equation to solve for P(E5). P(E4) + P(E5) = 0.3 2P(E5) + P(E5) = 0.3 3 P(E5) = 0.3 P(E4) + P(E5) = 0.3 0.1 0.3 0.1
Transcribed Image Text:A sample space consists of five simple events with P(E₁) = P(E₂) = 0.3, P(E3) = 0.1, and P(E4) = 2P(E5). and E5. Find the probabilities for simple events E4 Step 1 Recall that the sum of the probabilities for all simple events in a sample space equals 1. Since there are five simple events, E₁, E₂, E3, E4, E5, this yields the following equation. P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5) = 1 We are given that P(E₁) = P(E₂) = 0.3 and P(E3) = 0.1. Substitute these values into the above equation and simplify. P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5) = 1 0.3 +0.3 + 0.1 0.7 P(E5) 0.1 + P(E4) + P(E5) = 1 = 0.7 + P(E4) + P(E5) = 1 Step 2 We have simplified P(E₁) + P(E₂) + P(E3) + P(E4) + P(E5): = 1 to the equation P(EÂ) + P(E5) = 0.3. We are also given that P(E4) = 2P(E5). Note that both of these equations involve only P(E4) and P(E5). Substitute the second equation into the first equation to solve for P(E5). P(E4) + P(E5) = 0.3 2P(E5) + P(E5) = 0.3 3 P(E5) = 0.3 P(E4) + P(E5) = 0.3 0.1 0.3 0.1
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P(E5)=0.1

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