Step 3 Take the square root of both sides. Round your answer to one decimal place. a2 x 4864.54 a z 69.7 69.7 Step 4 Now, using the Law of Sines find the angle C. Round your answers to one decimal place. sin(C) sin(79°) 36 36 sin(79°) C = sin' Finally, because angles of a triangle are supplementary, B = 180° – 79° – ° (rounded to one decimal place)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.2: Trigonometric Functions Of Angles
Problem 26E
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Step 3
Take the square root of both sides. Round your answer to one decimal place.
a2 = 4864.54
a - 69.7
69.7
Step 4
Now, using the Law of Sines find the angle C. Round your answers to one decimal place.
sin(79°)
sin(C)
36
36 sin(79°)
C = sin
Finally, because angles of a triangle are supplementary,
B = 180° – 79° –
° (rounded to one decimal place)
Transcribed Image Text:Step 3 Take the square root of both sides. Round your answer to one decimal place. a2 = 4864.54 a - 69.7 69.7 Step 4 Now, using the Law of Sines find the angle C. Round your answers to one decimal place. sin(79°) sin(C) 36 36 sin(79°) C = sin Finally, because angles of a triangle are supplementary, B = 180° – 79° – ° (rounded to one decimal place)
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