Answer the steps. Step 3: Calculation of main reinforcement (longitudinal or steel):1. Design and detail a singly reinforced simply supported beam of Clear span5.5 m to support a working live load of 60 KN/m. use Fe 460 steel and M30grade concrete. Assume the support thickness as 220 mm. Over all depthof the beam is given as D=570 mm.(0.003 + f,/E,P = Pma =Pb0.008d = D - 25 =A = pbdb =AS fyMu =Ф As fy {d -Step 1: Determination of bending moment and shear force:1.7f'c bAs =2Total ultimate load = (Factor of safety x Dead load) + (Factor of safety x Liveload)Max value:Dead load = b XDX unit weight of concreteAsNo. of bars =Simply supported beam bending moment = Mu = Wle?/8 =Ans: NumberYDiameterStep 2: Check for depth:600(0.85)A, E(aPh =600 +f,( 0.003 +fy/E,Pmax =0.008= P maxfy ( 1Pmaxfy1.7f.Rumaxd =V R„b

Reinforced concrete is a mixture of traditional concrete cement and reinforcements. This mix is made…

Step 3: Calculation of main reinforcement (longitudinal or steel) 1. Design and detail a singly reinforced simply supported beam of Clear span 5.5 m to support a working live load of 60 KN/m. use Fe 460 steel and M30 grade concrete. Assume the support thickness as 220 mm. Over all depth of the beam is given as D=570 mm. 0.003+f/E, Pb P = Pmas = 0.008 d = D- 25 = A, = pbd b = -1 Mu = q As fy {d - s AS fy 1.7f'c Step 1: Determination of bending moment and shear force As = 2 Total ultimate load = (Factor of safety x Dead load) + (Factor of safety x Live load) Max value: Dead load = b XDX unit weight of concrete As No. of bars = %3D %3D Simply supported beam bending moment = Mu = Wle?/8 = Ans: Number XDiameter Step 2: Check for depth 開( 600 Po = (0.85)8, 600 +f, 0.003+f/E, Pmax = 0.008 Pmax fy 1.7f Rumas = pPmax M. d = Rb

Step 3: Calculation of main reinforcement (longitudinal or steel) 1. Design and detail a singly reinforced simply supported beam of Clear span 5.5 m to support a working live load of 60 KN/m. use Fe 460 steel and M30 grade concrete. Assume the support thickness as 220 mm. Over all depth of the beam is given as D=570 mm. 0.003+f/E, Pb P = Pmas = 0.008 d = D- 25 = A, = pbd b = -1 Mu = q As fy {d - s AS fy 1.7f'c Step 1: Determination of bending moment and shear force As = 2 Total ultimate load = (Factor of safety x Dead load) + (Factor of safety x Live load) Max value: Dead load = b XDX unit weight of concrete As No. of bars = %3D %3D Simply supported beam bending moment = Mu = Wle?/8 = Ans: Number XDiameter Step 2: Check for depth 開( 600 Po = (0.85)8, 600 +f, 0.003+f/E, Pmax = 0.008 Pmax fy 1.7f Rumas = pPmax M. d = Rb

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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