Step 2 Now write the derivative in terms of x by recalling that u = x³ = x + 8. [eu] = (eu) du dx [ex³-x+8] = (x³ -x + 8) (

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Step 2
Now write the derivative in terms of x by recalling that u = x²
dx
e+3
d[eu] = (eu) du
dx
dx
8] = (ex ³
- x + 8
-x+8
d
dx
- x + 8.
Transcribed Image Text:Step 2 Now write the derivative in terms of x by recalling that u = x² dx e+3 d[eu] = (eu) du dx dx 8] = (ex ³ - x + 8 -x+8 d dx - x + 8.
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