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Step 2 Find s(2) by substituting 2 for t in s(t)= -4.9t2 + 750. s(2) = -4.9([ + 750 II Submit Skip (you cannot come back)

Step 2 Find s(2) by substituting 2 for t in s(t)= -4.9t2 + 750. s(2) = -4.9([ + 750 II Submit Skip (you cannot come back)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What would I specfically but in each box for step 2. 

Tutorial Exercise Use the position function s(t) = -4.9t² + 750, which gives the height (In meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following. s(a)-s(t) a-t Find the velocity of the object when t = 2. lim ting Step 1 The velocity of the object when t = a= 2 2 Is s(2 ) - s(t) Ilm t-2 - t Step 2 Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750. s(2) = -4.9( 1² + 750 cip (you cannot come back)
Transcribed Image Text:Tutorial Exercise Use the position function s(t) = -4.9t² + 750, which gives the height (In meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following. s(a)-s(t) a-t Find the velocity of the object when t = 2. lim ting Step 1 The velocity of the object when t = a= 2 2 Is s(2 ) - s(t) Ilm t-2 - t Step 2 Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750. s(2) = -4.9( 1² + 750 cip (you cannot come back)
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what would i put in the box for step 3?

Tutorial Exercise Use the position function s(t) = -4.9t² + 750, which gives the height (in meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following. s(a)-s(t) Find the velocity of the object when t = 2. Step 1 The velocity of the object when t = a = Ilm t-2 s(2 Ⓒ2 )-s(t) 2 2 -t Step 2 Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750. s(2) = -4.9(22)² + 750 Submit 730.4 730.4 Step 3 Find the value of s(2) - s(t). 2 Is s(2) s(t)=19.6+750 - (-4.9t² + 750) Skip (you cannot come back)
Transcribed Image Text:Tutorial Exercise Use the position function s(t) = -4.9t² + 750, which gives the height (in meters) of an object that has fallen for t seconds from a height of 750 meters. The velocity at time t = a seconds is given by the following. s(a)-s(t) Find the velocity of the object when t = 2. Step 1 The velocity of the object when t = a = Ilm t-2 s(2 Ⓒ2 )-s(t) 2 2 -t Step 2 Find s(2) by substituting 2 for t In s(t) = -4.9t² + 750. s(2) = -4.9(22)² + 750 Submit 730.4 730.4 Step 3 Find the value of s(2) - s(t). 2 Is s(2) s(t)=19.6+750 - (-4.9t² + 750) Skip (you cannot come back)
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