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Step 1: State the hypotheses: Ho : μ = 8 H₁ : μ #8 This is two-tailed test. Step 2: Compute the test statistic: From CLT, if n >= 30, then sample mean is approximately normally distributed with mean, μ = μ and ox Step 3: Rejection rule: Reject H0 when p-value

Step 1: State the hypotheses: Ho : μ = 8 H₁ : μ #8 This is two-tailed test. Step 2: Compute the test statistic: From CLT, if n >= 30, then sample mean is approximately normally distributed with mean, μ = μ and ox Step 3: Rejection rule: Reject H0 when p-value

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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EXPLAIN STEP 1, 2, AND 3

please do this typewritten and completely so I will upvote. Thank you and much appreciated for the help.

Given that: Population mean, μ = 8 Sample mean, x = 7.9 Population standard deviation, o = 0.6 Sample size, n = 33 Level of significance, a = 0.10 Step 1: State the hypotheses: Ho : a = 8 H₁μ #8 This is two-tailed test. Step 2: Compute the test statistic: From CLT, if n >= 30, then sample mean is approximately normally distributed with mean, μ = μ and 0 = Step 3: Rejection rule: Reject H0 when p-value <a, otherwise do not reject it. Step 4: Compute the P-value by using the normal distribution table: 2P (Z ≤ z)=2P (Z ≤ -0.957) = 2 (0.169) =0.338 The P-value is 0.338. Step 5: Make Decision 0.338 > 0. 10 Decision: Do not reject HO Step 6: Conclusion: There is not enough evidence to reject the claim at 0.05 significance level. I-H₂ 67 7.9-8 0.6 = √33 = -0.957
Transcribed Image Text:Given that: Population mean, μ = 8 Sample mean, x = 7.9 Population standard deviation, o = 0.6 Sample size, n = 33 Level of significance, a = 0.10 Step 1: State the hypotheses: Ho : a = 8 H₁μ #8 This is two-tailed test. Step 2: Compute the test statistic: From CLT, if n >= 30, then sample mean is approximately normally distributed with mean, μ = μ and 0 = Step 3: Rejection rule: Reject H0 when p-value <a, otherwise do not reject it. Step 4: Compute the P-value by using the normal distribution table: 2P (Z ≤ z)=2P (Z ≤ -0.957) = 2 (0.169) =0.338 The P-value is 0.338. Step 5: Make Decision 0.338 > 0. 10 Decision: Do not reject HO Step 6: Conclusion: There is not enough evidence to reject the claim at 0.05 significance level. I-H₂ 67 7.9-8 0.6 = √33 = -0.957
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