Step 1 Recall the product rule, where both g and h are differentiable. d d + dx We are given the function f(x) = (8x2 – 3x)e*, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) = g(x)h(x). If we let g(x) = 8x2 – 3x, then h(x) is as follows. h(x) = * Step 2 In order to apply the product rule we must first find dx d and Doing so gives the following results. g(x) = 8x² – 3x d h(x) = ex dx
Step 1 Recall the product rule, where both g and h are differentiable. d d + dx We are given the function f(x) = (8x2 – 3x)e*, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) = g(x)h(x). If we let g(x) = 8x2 – 3x, then h(x) is as follows. h(x) = * Step 2 In order to apply the product rule we must first find dx d and Doing so gives the following results. g(x) = 8x² – 3x d h(x) = ex dx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![Step 1
Recall the product rule, where both g and h are differentiable.
d
d
d
9(x)hcx)] = 9(x) (n(x) + h(x) [gcx)]
dx
We are given the function f(x) = (8x² – 3x)e*, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) =
g(x)h(x). If we let
g(x) = 8x2
3x, then h(x) is as follows.
h(x) =
Step 2
d
In order to apply the product rule we must first find
dx
d
and
h(x). Doing so gives the following results.
g(x) =
8x? -
— Зх
d
g(x)
dx
h(x) =
et
d
=
dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3dbb19f-7b67-4a8a-b020-342febf8db53%2F6ba76384-875e-4e56-bff2-93cf0ef0d385%2F5etfk6i_processed.png&w=3840&q=75)
Transcribed Image Text:Step 1
Recall the product rule, where both g and h are differentiable.
d
d
d
9(x)hcx)] = 9(x) (n(x) + h(x) [gcx)]
dx
We are given the function f(x) = (8x² – 3x)e*, which we see is the product of two differentiable functions g(x) and h(x) such that f(x) =
g(x)h(x). If we let
g(x) = 8x2
3x, then h(x) is as follows.
h(x) =
Step 2
d
In order to apply the product rule we must first find
dx
d
and
h(x). Doing so gives the following results.
g(x) =
8x? -
— Зх
d
g(x)
dx
h(x) =
et
d
=
dx
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 3 images
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning