Step 1 LiW: H = 10:1:3 Valome lokx1xX 3と %3D = 3ox3m3 8= 1080 mm |br Detention thme ='15 mmute aj No. of betches im I hour = 60 - 4 Ams 15 Step 2 B Vodomme of tamk = filow in detention time 3oe = 1090メ 15 K = 2.079gm=2.08m 人= lor = 20-8m W = x = 2-08m %3D Ams H = 32 = 3x208 6-24m 9 Ete velocity = 1080 %3D
A rectangular sedimentation tank has dimensional proportions of 10:1:3 (L:W:H). If sedimentation is done in batch, the tank can cater 1080 m^3 in one hour, while the detention time for a continuous settling is 15 minutes on the same tank.
a) During batch sedimentation, how many batches is done in an hour?
b) Solve the dimensions of the tank.
c) If the critical settling velocity is 0.003m/s, how many percent of the solids will be settled down?
d) If the influent has a solids concentration of 230 mg/L and the effluent is 90% of the influent, compute the solids concentrations both at the underflow and the overflow.
e) Determine the filter area if the filter loading rate is 2.3 gal/d.ft.
ANSWER D AND E I PROVIDED SOME INFORMATION THANK YOU!
 alt="Step 1
L:w: H =
10:1:3
Val ome
loexIXX 32
%3D
= 3or?m3
8= lo80 m| hr
Detention tme ='15 mmute
9) No of bet ches in
I hour =
15
60
Ams
Step 2
B Vodomme of tamk =
filow in detention time
3oe =
1080メ 15
bo
K = 2.079gm = 2.08m
人= lor = 20.8m
W = x =
2.08m
Ams
H =
3 = 3X208 6-24m
1080
9 Et velocitg
setulng
%3D
wメル
2.08 x4 209
= 24.963 ml
= 0: 00 693mls
- 0-003 mls
Gitical seltding velocity =
1. of settled salid =
o.003
X100 = 43.264 % Arps
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