Please I want solution Step 1) Copy the following code into an editor.class JavaException {public static void main (String args[]){try {int d = 1;int n = 20;int fraction = n / d;int g[] = {1} ;g[20] = 100;}/*catch (Exception e){System.out.println("In the catchblock due to Exception = "+e);}*/catch (ArithmeticException e) {System.out.println("In the catchblock due to Exception = " + e);} catch(ArrayIndex0utOfBoundsException e) {System.out.println("In the catchblock due to Exception = " + e);}System.out.println("End Of Main");}}Step 2) Save the file & compile the code. Run theprogram using command, java JavaException.Step 3) Change the value of int d to 0. Save, Compile &Run the code..Step 4) Uncomment line #10 to line #12. Save, Compile& Run the code. what the result?

ArrayIndexOutOfBoundsException was thrown because we were trying to access an array element with an…

Step 1) Copy the following code into an editor. class JavaException { public static void main (String args[]) { try { int d = 1; int n = 20; int fraction = n / d; int g[] = { 1 }; g[20] = 100; } /*catch (Exception e){ System.out.println("In the catch block due to Exception = "+e); }*/ catch (ArithmeticException e) { System.out.println("In the catch block due to Exception = " + e); } catch (ArrayIndexoutOfBoundsException e) { System.out.println("In the catch block due to Exception = " + e); System.out.println("End Of Main"); } Step 2) Save the file & compile the code. Run the program using command, java JavaException. Step 3) Change the value of int d to 0. Save, Compile & Run the code.. Step 4) Uncomment line #10 to line #12. Save, Compile & Run the code. what the result?

Step 1) Copy the following code into an editor. class JavaException { public static void main (String args[]) { try { int d = 1; int n = 20; int fraction = n / d; int g[] = { 1 }; g[20] = 100; } /catch (Exception e){ System.out.println("In the catch block due to Exception = "+e); }/ catch (ArithmeticException e) { System.out.println("In the catch block due to Exception = " + e); } catch (ArrayIndexoutOfBoundsException e) { System.out.println("In the catch block due to Exception = " + e); System.out.println("End Of Main"); } Step 2) Save the file & compile the code. Run the program using command, java JavaException. Step 3) Change the value of int d to 0. Save, Compile & Run the code.. Step 4) Uncomment line #10 to line #12. Save, Compile & Run the code. what the result?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Please I want solution

Step 1) Copy the following code into an editor.
class JavaException {
public static void main (String args[])
{
try {
int d = 1;
int n = 20;
int fraction = n / d;
int g[] = {
1
} ;
g[20] = 100;
}
/*catch (Exception e){
System.out.println("In the catch
block due to Exception = "+e);
}*/
catch (ArithmeticException e) {
System.out.println("In the catch
block due to Exception = " + e);
} catch
(ArrayIndex0utOfBoundsException e) {
System.out.println("In the catch
block due to Exception = " + e);
}
System.out.println("End Of Main");
}
}
Step 2) Save the file & compile the code. Run the
program using command, java JavaException.
Step 3) Change the value of int d to 0. Save, Compile &
Run the code..
Step 4) Uncomment line #10 to line #12. Save, Compile
& Run the code. what the result?

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