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Step 1 Begin by rewriting the integral into the following form. du/dx du = xp Let u = X + 12x + 3x + 6 + 12.2 + 3r + 6 du = 3x + 24x + 3, dx 3x2 +24.r + 3 du x² + 8x + 1 dx = x3 + 12x2 + 3x + 6 3u 3u Step 2 Solve the new integral using the Gener Log Rule. Then, back-substitute x into the equation. (Re use absolute values where appropriate.) du = Inju| + C x² + 8x + 1 du x3 + 12x² + 3x + 6 dx = 3

Step 1 Begin by rewriting the integral into the following form. du/dx du = xp Let u = X + 12x + 3x + 6 + 12.2 + 3r + 6 du = 3x + 24x + 3, dx 3x2 +24.r + 3 du x² + 8x + 1 dx = x3 + 12x2 + 3x + 6 3u 3u Step 2 Solve the new integral using the Gener Log Rule. Then, back-substitute x into the equation. (Re use absolute values where appropriate.) du = Inju| + C x² + 8x + 1 du x3 + 12x² + 3x + 6 dx = 3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the indefinite integral. x + 8x + 1 dx x3 + 12x² + 3x + 6 Step 1 Begin by rewriting the integral into the following form. du/dx du = xp Let u = 12x+ 3x + 6 + r + 12 +3.x + 6 3x + 24x + 3 dx 32 +24.r + 3 du = du x2 + 8x + 1 dx = + 12x² + 3x + 6 3u 3u Step 2 Solve the new integral using the Gener Log Rule. Then, back-substitute x into the equation. (Remember to use absolute values where appropriate.) du = In|u| + C x2 + 8x + 1 du x3 + 12x² + 3x + 6 dx = 3.
Transcribed Image Text:Find the indefinite integral. x + 8x + 1 dx x3 + 12x² + 3x + 6 Step 1 Begin by rewriting the integral into the following form. du/dx du = xp Let u = 12x+ 3x + 6 + r + 12 +3.x + 6 3x + 24x + 3 dx 32 +24.r + 3 du = du x2 + 8x + 1 dx = + 12x² + 3x + 6 3u 3u Step 2 Solve the new integral using the Gener Log Rule. Then, back-substitute x into the equation. (Remember to use absolute values where appropriate.) du = In|u| + C x2 + 8x + 1 du x3 + 12x² + 3x + 6 dx = 3.
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