Step 1 :4.9668 g of Na2SO3 was dissolved in 30ml distilled water by heating. Step 2 : Then 6.0895g of CuCl2. H20 was dissolved in 20ml distilled water by stirring with a glass rod. The colour observed here was a deep blue/green Step 3 : The solution from step 1 was added to step 2 solution. Colour turned Light green. Step 4 : 20ml 0.001M H,SO4 was then added to the solution in Step 3 Step 5 : The solution was then funnelled using a buchner funnel, then washed three times with H2SO4 and washed three times with ethanol. The end product was solid white crystals, which weighed 2.4972 grams. Which ion is responsible for a change in colour in step 2? which gas is released when sulphuric Acid (H2SO4) is added to the mixture in step 4? What is the yield of the end product? Show all calculations What is the name of the end product? The white crystals?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Reactions
CuCl2(aq) + H20(1) + Na2SO3(aq) → NazSO4(aq) + 2HCI(aq) + 2CuCI(s)
SO3? (aq) + 2H*(aq) → SO2(g) + H20(1)
CuCl2(aq) + SO2(g) + 2H2O(1) → H2SO4(aq) + 2CUCI(s) + 2HCI(aq)
Transcribed Image Text:Reactions CuCl2(aq) + H20(1) + Na2SO3(aq) → NazSO4(aq) + 2HCI(aq) + 2CuCI(s) SO3? (aq) + 2H*(aq) → SO2(g) + H20(1) CuCl2(aq) + SO2(g) + 2H2O(1) → H2SO4(aq) + 2CUCI(s) + 2HCI(aq)
Step 1 :4.9668 g of Na2SO3 was dissolved in 30ml distilled water by heating.
Step 2 : Then 6.0895g of CuCl2. H20 was dissolved in 20ml distilled water by stirring with a glass
rod. The colour observed here was a deep blue/green
Step 3 : The solution from step 1 was added to step 2 solution. Colour turned Light green.
Step 4 : 20ml 0.001M H2S04 was then added to the solution in Step 3
Step 5 : The solution was then funnelled using a buchner funnel, then washed three times with
H,SO4 and washed three times with ethanol.
The end product was solid white crystals, which weighed 2.4972 grams.
Which ion is responsible for a change in colour in step 2?
which gas is released when sulphuric Acid (H2S04) is added to the mixture in step 4?
What is the yield of the end product? Show all calculations
What is the name of the end product? The white crystals?
Transcribed Image Text:Step 1 :4.9668 g of Na2SO3 was dissolved in 30ml distilled water by heating. Step 2 : Then 6.0895g of CuCl2. H20 was dissolved in 20ml distilled water by stirring with a glass rod. The colour observed here was a deep blue/green Step 3 : The solution from step 1 was added to step 2 solution. Colour turned Light green. Step 4 : 20ml 0.001M H2S04 was then added to the solution in Step 3 Step 5 : The solution was then funnelled using a buchner funnel, then washed three times with H,SO4 and washed three times with ethanol. The end product was solid white crystals, which weighed 2.4972 grams. Which ion is responsible for a change in colour in step 2? which gas is released when sulphuric Acid (H2S04) is added to the mixture in step 4? What is the yield of the end product? Show all calculations What is the name of the end product? The white crystals?
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