Steel DesignW21x62 steel is used as a beam simply supported over a spanof 8 m. The beam is laterally unsupported over the entire spanFy = 250 MPa.The properties of the section are as follows:Depth, d = 533 mmFlange width, bf = 210 mmFlange thickness, tf = 15.6 mmWeb thickness, tw = 10.2 mmRadius of gyration, rT = 53.34 mmSection modulus, Sx = 2,077 x 103 mm³a) Determine the value of the ratio L/rT.b) Determine the allowable bending stress in MPa.

Answered: Image /qna-images/answer/f583e319-bc3c-4f96-a681-4c41423b5292.jpg

Steel Design W21x62 steel is used as a beam simply supported over a span of 8 m. The beam is laterally unsupported over the entire spa Fy = 250 MPa. The properties of the section are as follows: Depth, d = 533 mm Flange width, bf = 210 mm

Steel Design W21x62 steel is used as a beam simply supported over a span of 8 m. The beam is laterally unsupported over the entire spa Fy = 250 MPa. The properties of the section are as follows: Depth, d = 533 mm Flange width, bf = 210 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.6 m long,…

Q: W 14 x 142 is used as a column having a length of 8.48 m. long. It is hinged at the r end and fixed…

A: Given data- Properties of W 14 x 142 A = 26967.69 mm2 d= 374.65 mm bf= 393.70 mm tf= 27.00 mm tw=…

Q: The frame shown below is unbraced against sidesway. Assume that all columns are W14 x 61 and that…

Q: Determine the design strength of the beam shown. Assume fy=345MPA and fc=21MP.. 3-22 mm 75 375 mm…

A: We have to determine the value of design strength of the beam shown as per the given data in the…

Q: Problem 3 of 3 A 15 ft long W8x40 wide flange column of A36 steel is fixed at the base and free at…

Q: A built-up section shown, 30 feet long, is fixed at both ends and braced in the weak direction at…

A: Given data:Section properties-

Q: A W24x76, A992 steel is to be used as simply supported beam to resist a concentrated load at…

A: Given data: Section properties of W24X76 Zx= 3280×103 mm3 Sx=2880×103 mm3 Strength reduction factor,…

Q: A 14 ft long W12 x 65 beam-column is part of a braced frame and supports service loads of Pp = 180 k…

A: W12x65 , Ag = 19.1 in2, Ix = 533 in4 , Lp = 11.9 ft and Lr = 35.1 ftLb = 14 ft , Cb = 1.0 Kx =…

Q: Given: Consider the floor frame below supports a 6-in. concrete floor. Assume the beams and girders…

Q: se Allowable Strength Design. Use A992 steel and select a W-shape for the following beam: •…

A: Given- Service dead load = 0.4 kips/ftService live load = 1.2 kips/ftdead load=10kiplive load=12…

Q: Determine the vertical deflection of end A. A downwards deflection is positive, while an upwards…

Q: HOMEWORK-1 - 3m· For the truss shown in the figure; a) Calculate the bar forces for F=4000 kg.

A: a.given that, F=4000kg 1-2=4m 1-3=3m 2-3=42+32=5m so, we have to calculate the bar force.

Q: as shown. It is used as a compression member to support a vertical load, P. The column is hinged on…

A: 2L 100x100x8 are welded togetherk = 0.70Use A36 steel (Fy = 248 MP a)Properties of an L 100x100x8:

Q: The steel beam AB has a uniformly distributed load (UDL) w1 = 6 kN/m acting along its full length L1…

A: Answer To calculate the deflection at midspan of a given simply supported beam we have f =…

Q: Q: Design the member AB within the frame shown. The applied load is a service load. Use Fy-50 ksi. k…

A: Axial compression member Service load= 300 kipLength of compression member = 15 ft.Steel Section =…

Q: Problem 4: Use A992 steel and select a W shape. The service dead load is 142 kips, and the service…

A: First we summarise the given data : Service dead load = 142 kips Service live load = 356 kips To…

Q: problem 7: Check whether the depth of a simply supported beam in the following case is Hequate or…

Q: An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange, and a…

A: Given:An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange,…

Q: 30kN/m. the beam is 12 meters long and is laterally supported at the midspan, and A572 Gr.50 steel…

A: Solution is as given below

Q: Consider the simply supported truss as defined in the figure and parameter table. Find the force in…

Q: Determine the design strength of the beam shown. Assume fy=345MPa and fc'=21MPa. 3-22 mm 375 mm 375…

A: We have to determine the value of design strength of the beam shown as per the given data in the…

Q: 3. Check the suitability of the W12x65 section made of A992 steel for the axial loads and moments…

A: Effective length of the column in x-axis buckling = Kx Lx= 1.4*14= 19.6 ft = 235.2 in Effective…

Q: A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7.8 m long,…

Q: Q2. Design the required tensile and compression rebars for the cross section shown below. Mu= 288…

A: for given cross section given b=250mm D=500mm MU=288KN-M FC=20 MPA FY=300MPA

Q: Find: Calculate the following: Figure a. The gross moment of inertia, Ig b. The location of the…

A: Moment of Inertia:The moment of inertia is defined as the amount indicated by the object opposing…

Q: W 14 x 142 is used as a column having a length of 9.21 m. long. It is hinged at the r end and fixed…

Q: The member shown in Figure has lateral support at points A, B, and C. Bending is about the strong…

A: Solution;

Q: A L1 B P1 L1 The steel beam ABC has a central point load P1 = 40 kN acting at a distance L1 = 2.8…

A: Given S355 Grade Universal beam is used.

Q: A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.8 m long,…

A: Given, The Given section : W12×79 properties of the given Section are as follows: A = 14,500 mm^2…

Q: P = L1 = L2= L1 Your Answer: P 195 2.50 4.5 Answer KN m m L2 ▷ View hint for Question 1 P The…

Q: A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long,…

A: In essential step in the design of a column is to determined whether the proposed dimensions will…

Q: Design all Tension members of the truss. Use A36 steel type. Dead Loads and Live loads are shown in…

Q: Design the most economical member for truss member L1 of the truss shown below. It is to consist of…

Q: Question 2: Use A572 Grade 50 steel and select the lightest W-shape for the beam-column shown below.…

Q: d. The end of each bar includes a standard 90 degree hoo m the outside face of the supporting…

Q: a) Determine the value of the ratio L/rT. b) Determine the allowable bending stress in MPa.

A: A simply supported W beam is and its sectional properties are provided. Depth, d = 533 mm Flange…

Q: Question 15 It is 6.9 m long, fixed at the top and bottom, and has additional A W12x79 of A573 Grade…

Q: A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset…

A: The order of the steel cross sections relies upon the heap that the part can convey prior to…

Q: A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 6.8 m long,…

Q: The beam-column in Figure P6.5-6 is braced against sidesway. Bending is about the major axis, and…

A: a} Calculate the factored load Calculate the factored bending moment at top of the beam

Q: A column is formed by welding two A36 MC sections back-to- back. The column is 32 feet long. With…

A: Following are the given information. A=6.45 in2, d=10 in bf=3.32 in, x=0.990 in Ix=102 in4, Iy=6.40…

Q: calculate the design strength

Q: The given girder has beams framing into it at the ends and at every L/3 point. The beam carries a…

A: A beam is a structural element that is predominantly subjected to transverse loads with minor axial…

Q: beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two…

A: Given:- W16 × 31 of A992 To find:- The beam is adequate for flexure and shear. a. Use LRFD. b. Use…

Q: DESIGN A SINGLE ANGLE MEMBER FOR THE TRUSS WHOSE TOP CHORD IS 36Kn compression, BOTTOM CHORD IS 30…

A: Given:- The force in the top chord of the truss = 36 kN (Compression) The force in the bottom chord…

Q: A simply supported beam with span of 6.5 m is subjected to a counterclockwise moment at the left…

Concept explainers

Bars

In civil engineering, bars refer to steel reinforcement bars or rebars. These are structural members primarily used for reinforcement purposes in masonry works. A bar is characterized by its cross-sectional area, which is negligible compared to its length. Bars are usually manufactured by steel which is uniform throughout the length, or by meshing multiple steel wires. Other materials of the bar include carbon steel, glass fiber, carbon fiber, and basalt fiber. The reinforcing bars are coated with epoxy resins and other materials to enhance some of their properties including corrosion resistance.

Question

Steel Design
W21x62 steel is used as a beam simply supported over a span
of 8 m. The beam is laterally unsupported over the entire span
Fy = 250 MPa.
The properties of the section are as follows:
Depth, d = 533 mm
Flange width, bf = 210 mm
Flange thickness, tf = 15.6 mm
Web thickness, tw = 10.2 mm
Radius of gyration, rT = 53.34 mm
Section modulus, Sx = 2,077 x 103 mm³
a) Determine the value of the ratio L/rT.
b) Determine the allowable bending stress in MPa.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given :

VIEW

Step 2: Solution :

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

6.9-2 Use A992 steel and select a structural tee shape for the top chord of the truss shown in Figure P6.9-2. This is the truss of Example 3.15. The trusses are spaced at 25 feet on centers and support W6 X 12 purlins at the joints and midway between the joints. The other pertinent data are summarized as follows: Metal deck: 2 psf Built-up roof: 5 psf Snow: 18 psf of horizontal roof projection a. Use LRFD. b. Use ASD. 46.6' 3' 3' 12' 3' 3' 2 @ -12' = 24- 2 @ 42' -12' = 24' 90 FIGURE P6.9-2
W 14 x 142 is used as a column having a length of 8.48 m. long. It is hinged at the r end and fixed at the lower end but there is a lateral bracing perpendicular to minor axis of the W section at a point 4.78 m. above the bottom support. It is assumed to be pinned connected at the bracing point. Using A 36 steel Fy= 248 MPa the NSCP Specificatioris. E, = 200000 MPa. Properties of W 14 x 142 A = 26967.69 mm2 d= 374.65 mm bf= 393.70 mm tf= 27.00 mm tw= 17.27 mm4 Ix= 695.11 x 106 mm4 Iy = 274.71 x 106 mm4 rx = 160.53 mm rY = 100.84 mm Assume: Kx = 0.80 for 8.48 m. length KY = 1.9 for the length on the upper support KY = 0.80 for the length on the bottom support Compute the slenderness ratio along y-axis. Please show clear solution thank you
Problem 3a. A compression member is built up from a W14 × 90 and a W10 > 49, both of A992 steel. Neglect flexural-torsional buckling W14 × 90 7" w10 x 49 KXL = KyL = 30 feet. Find the following: a. The KL/r b. The Euler Stress Fe c. The design strength for LRFD. d. The allowable strength for ASD. e. Is the section? Why?
AW14 x 43 column in a braced frame has a yield stress of 50 ksi and a height of 10 ft. The column is pinned at the top and bottom and has no intermediate bracing. Determine the available strength of the column considering the critical stress for flexural buckling. From AISC Manual Table 1-1, the properties of a W14 x 43 are: A = 12.6 in^2 tw = 0.305 in bf/2tf = 7.54 h/tw = 37.4 rx = 5.82 in ry = 1.89 in Ix = 428 in4 ly = 45.2 in4 G= 11,200 ksi J = 1.05 in^4 Cw=1950 in^6 What is the nominal axial strength considering flexural buckling stress of the column section (in kips). O 310 O 468 O 447 O 375 O 420 O 436 O 517 O 280
A cantilever beam having a 4m span carries a uniformly distributed load throughout its length. The beam is A36 steel with yield strength Fy = 248 MPa. The beam is not restrained against lateral buckling. The beam is W 21 by 62 steel shape, whose relevant properties are shown below: r = 0.053 m d = 0.533 m bf = 0.210 m tf = 0.016 m S = 0.002077 m3 Given this condition, solve for the allowable flexural stress in the compression flange. Use Cb = 1 as should be taken conservatively
: Determine the area of reinforcing steel required for the isolated T beam shown iff' =28 MPa, f = 420 MPa. effective width= 1400 mm- 400 mm 70 mm xx1mm 7mm M₂ = 100N.m
13 3. The cantilever beam has a T cross section and carries a vertical load at its free end as shown in the figure. At section s-s, find the (a) maximum tensile and compressive stress and (b) maximum shear stress. 2 kips S-S 14" 4 in + 43 + b-b 5 in 2 in 17" 5 in
For the hollow beam. Calculate the design. capacity, As = 2040mm ² Fy = 420 Mpa,Fc=25Mpa,Asmin check is not required
SOLVE please Determine the design bending strength of ISLB 350 @ 486 N/m, considering the beam to be laterally supported. Assume factored design shear force will not exceed 0.6 times the design shear strength of the cross-section. If it is used as simply support beam of unsupported length 5 m then determine the factored distributed load the beam can carry. Use Fe410 grade steel For ISLB 350 @ 486 N/m, section properties are as follows: h = 350 mm; b= 165 mm; t₁ = 11.4 mm; t = 7.4 mm; R₁ = 16 mm; Izz = 13158.3 × 104 mm²; I = 631.9 × 10¹ mm²; Zpz = 851.11 × 10³ mm³; Zez = 751.9 x 10³ mm³
Determine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, pinned at the top fixed at bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 1. Calculate the critical slenderness ratio of the member. a. 26.208 b. 45.882 c. 36.706 d. 27.529 2. calculate the nominal axial load capacity of the column a. 3104 kN b. 4851 kN c. 4213 kN d. 5344 kN 3. calculalte the service axial dead load if the service axial live load is twice as that of the dead load. Use LRFD. a. 1354 kN b. 992 kN c. 1093 kN d. 634 kN
Question 5: (Use a W12 section) Use A992 steel and select a W shape. a. Use LRFD. b. Use ASD. D= 340 kips L=670 kips 10' 35' 15' 10' Strong axis Weak axis FIGURE P4.7-5