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Steam at P1 = 1600 psi and T1 = 1000°F enters a turbine operating at steady state at a mass flow rate of mi= 2 x 10° lb/hr with 20% of the entering mass flow extracted at P2 = 160 psi and T2= 450°F. The rest of the steam exits as a two-phase liquid- vapor mixture at P3 = 1 psi, with a quality of x3 = 80%. Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of the turbine in Btu/hr.

Steam at P1 = 1600 psi and T1 = 1000°F enters a turbine operating at steady state at a mass flow rate of mi= 2 x 10° lb/hr with 20% of the entering mass flow extracted at P2 = 160 psi and T2= 450°F. The rest of the steam exits as a two-phase liquid- vapor mixture at P3 = 1 psi, with a quality of x3 = 80%. Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of the turbine in Btu/hr.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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State what to find , assumption, and a simple sketch of the turbine. and then solve for the work output. 

Chapter 4: Conservation of Energy Steam at \( P_1 = 1600 \) psi and \( T_1 = 1000^\circ F \) enters a turbine operating at steady state at a mass flow rate of \( m_1 = 2 \times 10^6 \) lb/hr, with 20% of the entering mass flow extracted at \( P_2 = 160 \) psi and \( T_2 = 450^\circ F \). The rest of the steam exits as a two-phase liquid-vapor mixture at \( P_3 = 1 \) psi, with a quality of \( x_3 = 80\% \). Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of the turbine in Btu/hr. **Given:** - \( P_1 = 1600 \) psi - \( P_2 = 160 \) psi - \( P_3 = 1 \) psi - \( T_1 = 1000^\circ F \) - \( T_2 = 450^\circ F \) - \( x_3 = 80\% \) - \( m_1 = 2 \times 10^6 \) lb/hr - \( m_2/m_1 = 0.20 \) **Find:** - Work output of the turbine per unit mass in Btu/lb - Power output of the turbine in Btu/hr **Turbine Sketch:** (Diagram showing the steam flow, indicating extraction and exit points, with respective pressures and qualities) **Assume:** (Assumptions list not provided here) **Property Data:** - \( h_1 = 1487.1 \) Btu/lb - \( h_2 = 1246.1 \) Btu/lb - \( h_3 = h_3 [P_3, x_3] \) - \( hf_3 = 69.74 \) Btu/lb - \( hg_3 = 1105.8 \) Btu/lb *Note: \( h_3 \) needs to be calculated based on \( P_3 \) and \( x_3 \).*
Transcribed Image Text:Chapter 4: Conservation of Energy Steam at \( P_1 = 1600 \) psi and \( T_1 = 1000^\circ F \) enters a turbine operating at steady state at a mass flow rate of \( m_1 = 2 \times 10^6 \) lb/hr, with 20% of the entering mass flow extracted at \( P_2 = 160 \) psi and \( T_2 = 450^\circ F \). The rest of the steam exits as a two-phase liquid-vapor mixture at \( P_3 = 1 \) psi, with a quality of \( x_3 = 80\% \). Determine the work output of the turbine per unit mass entering the turbine in Btu/lb and the power output of the turbine in Btu/hr. **Given:** - \( P_1 = 1600 \) psi - \( P_2 = 160 \) psi - \( P_3 = 1 \) psi - \( T_1 = 1000^\circ F \) - \( T_2 = 450^\circ F \) - \( x_3 = 80\% \) - \( m_1 = 2 \times 10^6 \) lb/hr - \( m_2/m_1 = 0.20 \) **Find:** - Work output of the turbine per unit mass in Btu/lb - Power output of the turbine in Btu/hr **Turbine Sketch:** (Diagram showing the steam flow, indicating extraction and exit points, with respective pressures and qualities) **Assume:** (Assumptions list not provided here) **Property Data:** - \( h_1 = 1487.1 \) Btu/lb - \( h_2 = 1246.1 \) Btu/lb - \( h_3 = h_3 [P_3, x_3] \) - \( hf_3 = 69.74 \) Btu/lb - \( hg_3 = 1105.8 \) Btu/lb *Note: \( h_3 \) needs to be calculated based on \( P_3 \) and \( x_3 \).*
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