Steam at 1.4 MPa and 350 °C enters an adiabatic turbine at a rate of 450 kg/hr. The exhaust pressure is 100 kPa. To start, assume the turbine is reversible. Neglect changes in kinetic and potential energy and assume steady flow. (a) Sketch this process on a T- s diagram.
Steam at 1.4 MPa and 350 °C enters an adiabatic turbine at a rate of 450 kg/hr. The exhaust pressure is 100 kPa. To start, assume the turbine is reversible. Neglect changes in kinetic and potential energy and assume steady flow. (a) Sketch this process on a T- s diagram.
Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Irreversible turbine
Steam at 1.4 MPa and 350 °C enters an adiabatic turbine at a rate of 450 kg/hr. The exhaust
pressure is 100 kPa. To start, assume the turbine is reversible. Neglect changes in kinetic
and potential energy and assume steady flow.
Sketch this process on a T - s diagram.
(a)
(b)
turbine.
Now, consider that the turbine is irreversible. We can define the adiabatic-turbine efficiency
nT as:
Find the temperature of the exhaust stream and the power produced by the
(c)
(d)
(e)
(1)
where h, is the inlet enthalpy, he,a is the actual exit enthalpy, and he,s is the isentropic exit
enthalpy. This quantity can be viewed as the ratio of the irreversible power to the reversible
power. Let's take n
0.8.
=
hi - he,a
hi - he,s
NT =
Draw the irreversible process on a T s diagram with a dashed line.
Find the power produced by the actual turbine and the actual exit enthalpy.
Calculate the rate of entropy generation."
Transcribed Image Text:4
Irreversible turbine
Steam at 1.4 MPa and 350 °C enters an adiabatic turbine at a rate of 450 kg/hr. The exhaust
pressure is 100 kPa. To start, assume the turbine is reversible. Neglect changes in kinetic
and potential energy and assume steady flow.
Sketch this process on a T - s diagram.
(a)
(b)
turbine.
Now, consider that the turbine is irreversible. We can define the adiabatic-turbine efficiency
nT as:
Find the temperature of the exhaust stream and the power produced by the
(c)
(d)
(e)
(1)
where h, is the inlet enthalpy, he,a is the actual exit enthalpy, and he,s is the isentropic exit
enthalpy. This quantity can be viewed as the ratio of the irreversible power to the reversible
power. Let's take n
0.8.
=
hi - he,a
hi - he,s
NT =
Draw the irreversible process on a T s diagram with a dashed line.
Find the power produced by the actual turbine and the actual exit enthalpy.
Calculate the rate of entropy generation.
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