Exercise 5.50The refrigerator shown in Fig operates atRefrigeratorB = 4.5steady state with a coefficient of performance of 4.5and a power input of 0.8 kW. Energy is rejected fromthe refrigerator to the surroundings at 20°C by heattransfer from metal coils whose average surfacetemperature is 28°C.Surroundings, 20°C- Coils, 28°CDetermine(a) the rate energy that is rejected, in kW.(b) the lowest theoretical temperature inside therefrigerator, in K.(c) the maximum theoretical power, in kW, that couldbe developed by a power cycle operating between thecoils and the surroundings. Would you recommendmaking use of this opportunity for developing power?0.8 kW49Chapler

here for a). apply Cop formula so we will get Q evaporator then by energy balance Qrejected=…

steady state with a coefficient of performance of 4.5 and a power input of 0.8 kW. Energy is rejected from the refrigerator to the surroundings at 20°C by heat transfer from metal coils whose average surface temperature is 28°C.

steady state with a coefficient of performance of 4.5 and a power input of 0.8 kW. Energy is rejected from the refrigerator to the surroundings at 20°C by heat transfer from metal coils whose average surface temperature is 28°C.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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