(AKS 24): A technology magazine finds data that suggests the prices of computerswith a specific configuration follow an approximately normal distribution with amean of $895.22 and a standard deviation of $109.30.The magazine wants to describe the percentage of these computers that are pricedbelow $600. WWhat Z-Score should they use?O a) z = 1.3%3DO b) z = -1.3c) z = -2.7%3Dd) z = 2.7Question 2 (1 point)(AKS 24): A set of laptop prices are normally distributed with a mean of $750 and a

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Answered: (AKS 24): A technology magazine finds…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The WAIS is an IQ test. Scores on the WAIS for the 20-34 age group are normally distributed with a mean 110 and a standard deviation of 25. Scores for the 60-64 age group are normally distributed with a mean of 90 and a standard deviation of 25. Find the percent of 20-34-year-olds that have an IQ greater than 120. a. 16% b. z= 0.4 or 40% c. 0.6554 or 65.54% d. 0.3446 or 34.46%
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.6 Mbps. The complete list of 50 data speeds has a mean of x=18.29 Mbps and a standard deviation of s=19.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? Question content area bottom Part 1 a. The difference is 54.3154.31 Mbps. (Type an integer or a decimal. Do not round.) Part 2 b. The difference is enter your response here standard deviations. (Round to two decimal places as needed.)
Consider the data from the Anthropology 105 class. The mean for women is 64.33 in and the standard deviation is 2.64 in. The average height of men in the US is approximately 5ft 10in. What proportion of women represented here are shorter than the average man?
If the mean height of bonsai trees is 52 cm with a standard deviation of 10 cm, what percent of the trees are above 82 cm? Select one: a. 0.3% O b. 82 O c. 3% O d. 0.15% Students at Roseville High School took an IQ test with a mean of 100 and a standard deviation of 15. Approximately, what percent of the students scored above 100? Answer: o represents the
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Please answer the following three multiple choice questions :) Summarized below are data for a study to see if hours of sleep per day for med and non-med students are the same: n x¯ s med students 25 5.8 0.83 non-med students 32 6.3 1.39 1. Find the test statistic (assume unequal standard deviation) A. -15.44 B. -5.69 C. -1.69 D. -1.81 2. Let tstat represent the value of the test statistic from the previous question. The degrees of freedom for the test are df = 52. To test the claim that the mean hours of sleep for med and non-med students is different, the P-value is calculated as: A. 2*pt( tstat, df=52, lower.tail = TRUE) B. 2*pt( tstat, df=52, lower.tail = FALSE) C. pt( tstat, df=52, lower.tail = TRUE) D. pt( tstat, df=52, lower.tail = FALSE) 3. The correct P-value is 0.098. At α = 0.05, we A. reject H0. The claim that means are different is not supported. B. reject H0. The claim that means are different is supported. C. fail to reject…
Consider the following data set. You may assume that the mean of this data set is x¯ = 7. 8 10 3 5 7 5 11 a) Find the range of the data set. b) Find the standard deviation of the data set. c) How many of the seven data points lie within one standard deviation of the mean?
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?
Q. 2. Suppose Country B's government now reports that its population mean disposable household income is $1,000 per month, with a standard deviation of $150. Country A's population mean is $1,100, with a standard deviation of $310. a. b. Which country has more variation in income? Explain using popular phrases, such as "gap between rich and poor." Each country defines the poverty level to be $755. If you assume that income has a normal distribution, find the probability that a household's income is below the poverty level in i. Country A ii. Country B Does it seem reasonable to assume a normal distribution? In general, is income symmetric or skewed?
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 71.7 Mbps. The complete list of 50 data speeds has a mean of x = 15.45 Mbps and a standard deviation of s = 21.16 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to az score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? a. The difference is Mbps. (Type an integer or a decimal. Do not round.)
A. Sam's times varied more over the season that Mike's times. B. Sam's times varied about the same over the season as Brett's times. C. Brett's times varied more over the season than Mike's times. D. Mike's times varied more over the season than Brett's times.
Q) The RATES of a SWEET BOX follows a normal distribution with a mean of $2.20 and a standard deviation of $0.20. Find the RATE for which 10.23% of sweet boxes are exceeded. Round your answer to nearest cent (hundredth) if necessary.

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