**Evaluate the given expression and express the result using the usual format:** \( ^{54}P_2 \) \[ ^{54}P_2 = \, \boxed{} \] **Explanation:** The expression \( ^{54}P_2 \) represents a permutation calculation where you are selecting and arranging 2 items out of a total of 54. The formula for permutations, where order matters, is given by: \[ nPm = \frac{n!}{(n-m)!} \] In this case, \( n = 54 \) and \( m = 2 \). Therefore, the calculation is: \[ ^{54}P_2 = \frac{54!}{(54-2)!} = \frac{54!}{52!} \] Simplifying further, since 54 factorial (54!) divided by 52 factorial (52!) results in multiplying the integers 54 and 53: \[ ^{54}P_2 = 54 \times 53 = 2862 \] So the final result is: \[ ^{54}P_2 = \, \boxed{2862} \]
**Evaluate the given expression and express the result using the usual format:** \( ^{54}P_2 \) \[ ^{54}P_2 = \, \boxed{} \] **Explanation:** The expression \( ^{54}P_2 \) represents a permutation calculation where you are selecting and arranging 2 items out of a total of 54. The formula for permutations, where order matters, is given by: \[ nPm = \frac{n!}{(n-m)!} \] In this case, \( n = 54 \) and \( m = 2 \). Therefore, the calculation is: \[ ^{54}P_2 = \frac{54!}{(54-2)!} = \frac{54!}{52!} \] Simplifying further, since 54 factorial (54!) divided by 52 factorial (52!) results in multiplying the integers 54 and 53: \[ ^{54}P_2 = 54 \times 53 = 2862 \] So the final result is: \[ ^{54}P_2 = \, \boxed{2862} \]
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Evaluate the given expression and express the result using the usual format:**
\( ^{54}P_2 \)
\[ ^{54}P_2 = \, \boxed{} \]
**Explanation:**
The expression \( ^{54}P_2 \) represents a permutation calculation where you are selecting and arranging 2 items out of a total of 54. The formula for permutations, where order matters, is given by:
\[ nPm = \frac{n!}{(n-m)!} \]
In this case, \( n = 54 \) and \( m = 2 \). Therefore, the calculation is:
\[ ^{54}P_2 = \frac{54!}{(54-2)!} = \frac{54!}{52!} \]
Simplifying further, since 54 factorial (54!) divided by 52 factorial (52!) results in multiplying the integers 54 and 53:
\[ ^{54}P_2 = 54 \times 53 = 2862 \]
So the final result is:
\[ ^{54}P_2 = \, \boxed{2862} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F508ee786-e013-45c0-a264-dadcc72c168c%2Fcc92a38f-076d-43ee-aa84-73d3150b7100%2Fzhkavjd.jpeg&w=3840&q=75)
Transcribed Image Text:**Evaluate the given expression and express the result using the usual format:**
\( ^{54}P_2 \)
\[ ^{54}P_2 = \, \boxed{} \]
**Explanation:**
The expression \( ^{54}P_2 \) represents a permutation calculation where you are selecting and arranging 2 items out of a total of 54. The formula for permutations, where order matters, is given by:
\[ nPm = \frac{n!}{(n-m)!} \]
In this case, \( n = 54 \) and \( m = 2 \). Therefore, the calculation is:
\[ ^{54}P_2 = \frac{54!}{(54-2)!} = \frac{54!}{52!} \]
Simplifying further, since 54 factorial (54!) divided by 52 factorial (52!) results in multiplying the integers 54 and 53:
\[ ^{54}P_2 = 54 \times 53 = 2862 \]
So the final result is:
\[ ^{54}P_2 = \, \boxed{2862} \]
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