When I examine the design of an experiment, I find that it fell victim to the Fundamental Threat to good research. What have Idiscovered?A confounding variableThat more than one IV was used.That the investigator violated the ethical principle of beneficence.That the alpha level picked by the researcher was too small.

Answered: When I examine the design of an…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher is conducting an experiment to evaluate the effectiveness of cognitive-behavioral therapy in treating eating disorders. The mean eating disorder score in clinical population of people suffering from the disorder is μ = 75. The results of the experiment will be examined by a z -test, two-tails. Which of the following is the correct statement of the alternative hypothesis, H1?A. μ = 75 (i.e., the treatment has a significant effect).B. μ ≠ 75 (i.e., the treatment has no significant effect).C. μ ≠ 75 (i.e., the treatment has a significant effect).D. μ = 75 (i.e., the treatment has no significant effect).
To combat antibiotic resistance, the Quality Improvement Consortium recommends a throat swab to confirm strep throat before a physician prescribes antibiotics to children under age 5. Nationally, 40 percent of children under 5 who received antibiotics did not have a throat swab. The Colorado Department of Health took a random sample of 100 children under the age of 5 who received antibiotics for throat infections and found that 30 did not have a throat swab. At α = .05, is this a statistically significant reduction over last year’s national rate of 40 percent? (a-1) Choose the correct null and alternative hypotheses. H0: π ≥ .40 vs. H1: π < .40 H0: π ≤ .40 vs. H1: π > .40 H0: π = .40 vs. H1: π ≠ .40 (a-2) Calculate the critical value. (A negative value should be indicated by a minus sign. Round your answer to 3 decimal places.) Critical value (a-3) Calculate the test statistic. (A negative value should be indicated by a minus sign. Round your…
Apple, Inc. reported that "0.5% (0.005) of participants received irregular pulse notifications indicative of possible AFib" which is a dangerous heart condition that needs an immediate trip to the emergency room. To improve benefits of pulse notifications, it is important to identify the percentage of people receiving false notifications. A cardiologist is concerned that the percentage of people who actually have these types of irregular heartbeats is not accurate. The doctor randomly selected a simple random sample of 2315 adults who own Apple watches and asked if they have received one of these irregular heartbeat notifications. Nine of the respondents reported receiving such a notification. Does this evidence support the cardiologists claim that the percentage of people who receive notifications of irregular heartbeats is not 0.5% (0.005)? Can the conditions for the 1-proportion Z- test be met? No, normality cannot be met. Yes, all conditions are met. No, some part of the binomial…
Researchers have suggested that sleep apnoea (the tendency to occasionally stop breathing when asleep) may worsen the effects of allergen-induced asthma. To investigate this possibility, Johnson and colleagues (2015), compared two groups of rats, a normal healthy non-allergic group, and a second group that were mildly allergic to ovalbumin. They subjected these rats to one of two treatments – 1) a 10-minute period of induced hypoxia (oxygen down to 10% of the air), representing the kind of temporary hypoxia that sufferers of sleep apnoea may be subjected to, and 2) a control (normal air) group. They then compared the respiratory function of both groups in these two treatments by using a two-factor ANOVA. What are the 3 null hypotheses are being tested in the ANOVA? What is the result of the test of the interaction effect from this analysis? What would be the most correct interpretation this result, based on the plot of means? Source df F P Rat type 1…
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State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
A new reading program may reduce the number of elementary school students who read below grade level. The company that developed this program supplied materials and teacher training for a large-scale test involving nearly 8,400 children in several different school districts. Statistical analysis of the results showed that the percentage of students who did not meet the grade-level goal was reduced from 14.7% to 14%. The hypothesis that the new reading program produced no improvement was rejected with a P-value of 0.026. Complete parts a) and b) below. a) Explain what the P-value means in this context. Choose the correct answer below. OA. There is a 97.4% chance of seeing a sample proportion of 14.7% (or more) of students failing the test by natural sampling variation if 14% is the true population value. B. There is only a 2.6% chance of seeing a sample proportion of 14.7% (or more) of students failing the test by natural sampling variation if 14% is the true population value. OC. There…
Reggie is running his stats for a project he just finished. He had participants came in to the lab and gave them a drug treatment (either a control or an experimental compound) at different times during the day (morning, afternoon, and night). Each participant went through all off of the conditions. He ran an ANOVA and tested for the main effects and their interaction. Assuming that only the main effects (and not the interaction) came back significant, interpret his results (no need to include tests statistics).

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