You are conducting a multinomial hypothesis test for the claim that all 5 categories are equally likely to be selected. Complete the table. | Category | Observed Frequency | Expected Frequency | Squared Pearson Residual | |----------|--------------------|--------------------|---------------------------| | A | 18 | | | | B | 16 | | | | C | 10 | | | | D | 11 | | | | E | 25 | | | What is the chi-square test statistic for this data? \[ x^2 = \, \] Report all answers accurate to three decimal places. **Question Help:** [Message instructor] **Submit Question**
You are conducting a multinomial hypothesis test for the claim that all 5 categories are equally likely to be selected. Complete the table. | Category | Observed Frequency | Expected Frequency | Squared Pearson Residual | |----------|--------------------|--------------------|---------------------------| | A | 18 | | | | B | 16 | | | | C | 10 | | | | D | 11 | | | | E | 25 | | | What is the chi-square test statistic for this data? \[ x^2 = \, \] Report all answers accurate to three decimal places. **Question Help:** [Message instructor] **Submit Question**
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 1
Denote Oi as the observed frequency (i =A, B, C, D, E) and Ei as the expected frequency(i =A, B, C, D, E). Here, the sample size, n=.
The expected frequency will be (80)/5≈16.
Test statistic:
The formula for the test statistic is χ2 = ∑ [(Oi – Ei)2 / Ei], summed over all i .
The Table calculates [(Oi – Ei)2 / Ei]for each (i). So, the value in the first cell will be (18– 16)2 / 16 ≈ 0.25.
The test statistic value can be calculated by adding all these cell values.
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