2. 3. If an aircraft is present in a certain area, a radar detects it and generates an alarm signal with probability 0,9. If an aircraft is not present, the radar generates a (false) alarm, with probability 0.05. We assume that an aircraft is present with probability 0.1. What is the probability that the radar does not generate an alarm signal? B = {Alarn} ļ A = { Arcraft) P(BITB) = 0.9 P (B₁A)=0.05 P(BIA) = 0.1 P(BIA) = 0.95 P(A) = 0.1 P (BNA) = P(BIA) P(A) = 0.1*0.1 0.01 fx (x) = The channel power gain of a wireless communication channel can be modeled by an exponential RV X, with average (mean) is equal to 3. Find Pr{X > 2|X > 1}. l^ = e + -K x>0 ке ECO+ + + ² ([X²+] E[x] = = = L -da P(x > 2/^ > 1) = P(x > 2) = F₁*² = 1-c² = 1-e²²

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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solve the second question please , last question in the picture 

2.
3.
If an aircraft is present in a certain area, a radar detects it and generates an alarm
signal with probability 0,9. If an aircraft is not present, the radar generates a (false) alarm,
with probability 0.05. We assume that an aircraft is present with probability 0.1. What is the
probability that the radar does not generate an alarm signal?
B = {Alarn}
ļ
A = { Arcraft)
P(BITB) = 0.9
P (B₁A)=0.05
P(BIA) = 0.1
P(BIA) = 0.95
P(A) = 0.1
P (BNA) = P(BIA) P(A) = 0.1*0.1
0.01
fx (x) =
The channel power gain of a wireless communication channel can be modeled by an
exponential RV X, with average (mean) is equal to 3. Find Pr{X > 2|X > 1}.
l^
=
e
+
-K
x>0
ке
ECO+ + + ² ([X²+]
E[x] = =
=
L
-da
P(x > 2/^ > 1) = P(x > 2) = F₁*² = 1-c²
= 1-e²²
Transcribed Image Text:2. 3. If an aircraft is present in a certain area, a radar detects it and generates an alarm signal with probability 0,9. If an aircraft is not present, the radar generates a (false) alarm, with probability 0.05. We assume that an aircraft is present with probability 0.1. What is the probability that the radar does not generate an alarm signal? B = {Alarn} ļ A = { Arcraft) P(BITB) = 0.9 P (B₁A)=0.05 P(BIA) = 0.1 P(BIA) = 0.95 P(A) = 0.1 P (BNA) = P(BIA) P(A) = 0.1*0.1 0.01 fx (x) = The channel power gain of a wireless communication channel can be modeled by an exponential RV X, with average (mean) is equal to 3. Find Pr{X > 2|X > 1}. l^ = e + -K x>0 ке ECO+ + + ² ([X²+] E[x] = = = L -da P(x > 2/^ > 1) = P(x > 2) = F₁*² = 1-c² = 1-e²²
Expert Solution
Step 1

Hint:

Use the Conditional Probability theorem as; P(A|B)=PABP(B)

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