23 3. In a pizza takeout restaurant, the following probability distribution was obtained. The random variable x represents the number of toppings for a large pizza. Find the mean and standard deviation. The table below is partially completed. Finish it and use the results to find the mean and standard deviation. P(x) | xP(x) (x -)(x-u)² 4)²P(x) wwww wwww wwww 0.36 -1.86 3.4596 1.245456 0.08 -0.86 0.7396 0.059168 0.08 1. 0.20 0.4 0.14 0.0196 0.00392 0.06 0.30 A. mean: 0.48; standard deviation: 1.66 B. mean: 1.86; standard deviation: 1.66 C. mean: 0.48; standard deviation: 2.76 D. mean: 1.86; standard deviation: 2.76 mean: 1.86; standard deviation: 1.31 E. An airline reports that it has been experiencing a 20% rate of no-shows on advanced reservations. Among 230 advanced reservations, find the probability that there will be 42 no-shows. Use continuity correction and the standard normal distribution table t approximate the binomial probability.

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3. In a pizza takeout restaurant, the following probability distribution was obtained. The random
variable x represents the number of toppings for a large pizza. Find the mean and standard
deviation.
The table below is partially completed. Finish it and use the results to find the mean and
standard deviation.
P(x) | xP(x) (x -)(x-u)²
4)²P(x)
wwww
wwww
wwww
0.36
-1.86
3.4596
1.245456
0.08
-0.86
0.7396
0.059168
0.08
1.
0.20
0.4
0.14
0.0196
0.00392
0.06
0.30
A. mean: 0.48; standard deviation: 1.66
B. mean: 1.86; standard deviation: 1.66
C. mean: 0.48; standard deviation: 2.76
D. mean: 1.86; standard deviation: 2.76
mean: 1.86; standard deviation: 1.31
E.
An airline reports that it has been experiencing a 20% rate of no-shows on advanced
reservations. Among 230 advanced reservations, find the probability that there will be
42 no-shows. Use continuity correction and the standard normal distribution table t
approximate the binomial probability.
Transcribed Image Text:23 3. In a pizza takeout restaurant, the following probability distribution was obtained. The random variable x represents the number of toppings for a large pizza. Find the mean and standard deviation. The table below is partially completed. Finish it and use the results to find the mean and standard deviation. P(x) | xP(x) (x -)(x-u)² 4)²P(x) wwww wwww wwww 0.36 -1.86 3.4596 1.245456 0.08 -0.86 0.7396 0.059168 0.08 1. 0.20 0.4 0.14 0.0196 0.00392 0.06 0.30 A. mean: 0.48; standard deviation: 1.66 B. mean: 1.86; standard deviation: 1.66 C. mean: 0.48; standard deviation: 2.76 D. mean: 1.86; standard deviation: 2.76 mean: 1.86; standard deviation: 1.31 E. An airline reports that it has been experiencing a 20% rate of no-shows on advanced reservations. Among 230 advanced reservations, find the probability that there will be 42 no-shows. Use continuity correction and the standard normal distribution table t approximate the binomial probability.
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