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**Normal Distribution Problem Example** A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 194.1 cm and a standard deviation of 1.1 cm. **Problem:** Find \( P_{77} \), which is the length separating the shortest 77% of rods from the longest 23%. **Inputs:** - \( P_{77} \) = ________ cm - \( (z = ________ ) \) **Instructions:** Shade the area to the left of a value on the normal distribution graph. Click and drag the arrows to adjust the values. **Graph Description:** The graph displays a normal distribution curve, which is symmetrical and bell-shaped, centered around 0. The shaded area on the left side of the curve represents the cumulative distribution up to the value in question, illustrating the probability or percentage of data points falling within that range. **Submit Question Button:** Once inputs are provided, click "Submit Question" to process the calculation based on the provided values.​

**Normal Distribution Problem Example** A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 194.1 cm and a standard deviation of 1.1 cm. **Problem:** Find \( P_{77} \), which is the length separating the shortest 77% of rods from the longest 23%. **Inputs:** - \( P_{77} \) = ________ cm - \( (z = ________ ) \) **Instructions:** Shade the area to the left of a value on the normal distribution graph. Click and drag the arrows to adjust the values. **Graph Description:** The graph displays a normal distribution curve, which is symmetrical and bell-shaped, centered around 0. The shaded area on the left side of the curve represents the cumulative distribution up to the value in question, illustrating the probability or percentage of data points falling within that range. **Submit Question Button:** Once inputs are provided, click "Submit Question" to process the calculation based on the provided values.​

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Normal Distribution Problem Example** A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 194.1 cm and a standard deviation of 1.1 cm. **Problem:** Find \( P_{77} \), which is the length separating the shortest 77% of rods from the longest 23%. **Inputs:** - \( P_{77} \) = ________ cm - \( (z = ________ ) \) **Instructions:** Shade the area to the left of a value on the normal distribution graph. Click and drag the arrows to adjust the values. **Graph Description:** The graph displays a normal distribution curve, which is symmetrical and bell-shaped, centered around 0. The shaded area on the left side of the curve represents the cumulative distribution up to the value in question, illustrating the probability or percentage of data points falling within that range. **Submit Question Button:** Once inputs are provided, click "Submit Question" to process the calculation based on the provided values.​
Transcribed Image Text:**Normal Distribution Problem Example** A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 194.1 cm and a standard deviation of 1.1 cm. **Problem:** Find \( P_{77} \), which is the length separating the shortest 77% of rods from the longest 23%. **Inputs:** - \( P_{77} \) = ________ cm - \( (z = ________ ) \) **Instructions:** Shade the area to the left of a value on the normal distribution graph. Click and drag the arrows to adjust the values. **Graph Description:** The graph displays a normal distribution curve, which is symmetrical and bell-shaped, centered around 0. The shaded area on the left side of the curve represents the cumulative distribution up to the value in question, illustrating the probability or percentage of data points falling within that range. **Submit Question Button:** Once inputs are provided, click "Submit Question" to process the calculation based on the provided values.​
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It is given that the mean is 194.1 and the standard deviation is 1.1.

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