static int count=0; static void printOutput(ArrayList arr){ count++; int sum=0; for(int i=0;i arr,int i,int n) { if(n==0){ printOutput(arr); } for(int j = i; j <= n; j++) { arr.add(j); findways (arr, j, n: n - i); arr.remove( index: arr.size() - 1); } } public static void main(String] args)throws IOException { BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int n=Integer.parseInt(br.readLine()); ArrayList arr = new ArrayList<>(); findways(arr, : 1,n); System.out.println("total="+(count-1));
static int count=0; static void printOutput(ArrayList arr){ count++; int sum=0; for(int i=0;i arr,int i,int n) { if(n==0){ printOutput(arr); } for(int j = i; j <= n; j++) { arr.add(j); findways (arr, j, n: n - i); arr.remove( index: arr.size() - 1); } } public static void main(String] args)throws IOException { BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int n=Integer.parseInt(br.readLine()); ArrayList arr = new ArrayList<>(); findways(arr, : 1,n); System.out.println("total="+(count-1));
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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My question regarding the recursion part:
1. After calling the recursion in void main, the line "for(int j = i; j <= n; j++)" tells us the recursive method will call itself for n times. If I input "5", how come there are 6 total different permutations (or input "6", total = 10, etc.)? If the recursive method gets called n times, shouldnt there be n different permutations?
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