Statements Reasons 1.) AABC and ADEF; mLC = MLDFE - 90: 1) AB a DE ; BC EF 2.) 2.) There is a point G on the ray opposite FD such that FC CA 3.) 3.) Draw GE 4.) )90+M2GFE = 180 5.) ) MLGFB - 90 6.) )ZGFE LC 7.) 04ABC AGEF 8.) A GE 9.) CE DE 10.) 2G 4D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 68E
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Statements
Reasons
1.) AABC and ADEF ; mLC = MLDFE = 90: 1.)
AB DE ; BC EF
%3D
2.)
2.) There is a point G on the ray opposite FD
such that FG a CA
3.)
3.) Draw GE
4.)
4.) 90 + MLGFE = 180
5.)
5.) MLGFB = 90
6.)
6.) ZGFE = LC
7.)
7.) AABC = AGEF
8.)
8.) AB = GE
9.)
9.) GE = DE
10.)
10.) 2G a LD
Transcribed Image Text:Statements Reasons 1.) AABC and ADEF ; mLC = MLDFE = 90: 1.) AB DE ; BC EF %3D 2.) 2.) There is a point G on the ray opposite FD such that FG a CA 3.) 3.) Draw GE 4.) 4.) 90 + MLGFE = 180 5.) 5.) MLGFB = 90 6.) 6.) ZGFE = LC 7.) 7.) AABC = AGEF 8.) 8.) AB = GE 9.) 9.) GE = DE 10.) 10.) 2G a LD
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