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Statements Reasons 1.) AABC and ADEF; mLC = MLDFE - 90: 1) AB a DE ; BC EF 2.) 2.) There is a point G on the ray opposite FD such that FC CA 3.) 3.) Draw GE 4.) )90+M2GFE = 180 5.) ) MLGFB - 90 6.) )ZGFE LC 7.) 04ABC AGEF 8.) A GE 9.) CE DE 10.) 2G 4D

Statements Reasons 1.) AABC and ADEF; mLC = MLDFE - 90: 1) AB a DE ; BC EF 2.) 2.) There is a point G on the ray opposite FD such that FC CA 3.) 3.) Draw GE 4.) )90+M2GFE = 180 5.) ) MLGFB - 90 6.) )ZGFE LC 7.) 04ABC AGEF 8.) A GE 9.) CE DE 10.) 2G 4D

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Statements Reasons 1.) AABC and ADEF ; mLC = MLDFE = 90: 1.) AB DE ; BC EF %3D 2.) 2.) There is a point G on the ray opposite FD such that FG a CA 3.) 3.) Draw GE 4.) 4.) 90 + MLGFE = 180 5.) 5.) MLGFB = 90 6.) 6.) ZGFE = LC 7.) 7.) AABC = AGEF 8.) 8.) AB = GE 9.) 9.) GE = DE 10.) 10.) 2G a LD
Transcribed Image Text:Statements Reasons 1.) AABC and ADEF ; mLC = MLDFE = 90: 1.) AB DE ; BC EF %3D 2.) 2.) There is a point G on the ray opposite FD such that FG a CA 3.) 3.) Draw GE 4.) 4.) 90 + MLGFE = 180 5.) 5.) MLGFB = 90 6.) 6.) ZGFE = LC 7.) 7.) AABC = AGEF 8.) 8.) AB = GE 9.) 9.) GE = DE 10.) 10.) 2G a LD
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