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State which property of determinants is illustrated in this equation. 1-4 6 07= 2 5 -1 2 1-4 6 0 8 -5 5 -1 2 Choose the correct answer below. A. If a multiple of one row of A is added to another row to produce matrix B, then det B = det A. B. IfA and B are square matrices, then det AB = (det A)(det B). O C. If two rows of A are interchanged to produce B, then det B = -det A. O D. If one row of A is multiplied by k to produce B, then det B = k • det A.

State which property of determinants is illustrated in this equation. 1-4 6 07= 2 5 -1 2 1-4 6 0 8 -5 5 -1 2 Choose the correct answer below. A. If a multiple of one row of A is added to another row to produce matrix B, then det B = det A. B. IfA and B are square matrices, then det AB = (det A)(det B). O C. If two rows of A are interchanged to produce B, then det B = -det A. O D. If one row of A is multiplied by k to produce B, then det B = k • det A.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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State which property of determinants is illustrated in this equation. | 1-4 6 2 07= 5 -1 2 1-4 6 0 8 -5 5 -1 2 Choose the correct answer below. A. If a multiple of one row of A is added to another row to produce matrix B, then det B = det A. B. IfA and B are square matrices, then det AB = (det A)(det B). O C. If two rows of A are interchanged to produce B, then det B = -det A. O D. If one row of A is multiplied by k to produce B, then det B = k • det A.
Transcribed Image Text:State which property of determinants is illustrated in this equation. | 1-4 6 2 07= 5 -1 2 1-4 6 0 8 -5 5 -1 2 Choose the correct answer below. A. If a multiple of one row of A is added to another row to produce matrix B, then det B = det A. B. IfA and B are square matrices, then det AB = (det A)(det B). O C. If two rows of A are interchanged to produce B, then det B = -det A. O D. If one row of A is multiplied by k to produce B, then det B = k • det A.
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