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State the restriction on the domain and then find the inverse of the function. f(x) = x² - 6x Domain of f(x) is [-9, ∞); Domain of f(x) is [-3, %); Domain of f(x) is [3, ∞); ƒ¹(x)=√√x+9+3 ƒ¯¹(x) = √√x+9 +3 f ƒ ¹(x)=√√x+9+3 ƒ−¹(x) = √√x +9 −3 Domain of f(x) is [3, ∞);

State the restriction on the domain and then find the inverse of the function. f(x) = x² - 6x Domain of f(x) is [-9, ∞); Domain of f(x) is [-3, %); Domain of f(x) is [3, ∞); ƒ¹(x)=√√x+9+3 ƒ¯¹(x) = √√x+9 +3 f ƒ ¹(x)=√√x+9+3 ƒ−¹(x) = √√x +9 −3 Domain of f(x) is [3, ∞);

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.7: Inverse Functions
Problem 2SE: Why do we restrict the domain of the function f(x)=x2 to find the function's inverse?
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8 of 12 State the restriction on the domain and then find the inverse of the function. f(x) = x² - 6x Domain of f(x) is [-9, ∞); Domain of f(x) is [-3, ∞); Domain of f(x) is [3, ∞); Domain of f(x) is [3, ∞); -1 ƒ¯¹(x) = √√x + 9 +3 -1 ƒ−¹(x) = √√√x+9+3 ƒ¯¹(x) = √√√x+9 +3 ƒ¯¹(x) = √√x+9 − 3
Transcribed Image Text:8 of 12 State the restriction on the domain and then find the inverse of the function. f(x) = x² - 6x Domain of f(x) is [-9, ∞); Domain of f(x) is [-3, ∞); Domain of f(x) is [3, ∞); Domain of f(x) is [3, ∞); -1 ƒ¯¹(x) = √√x + 9 +3 -1 ƒ−¹(x) = √√√x+9+3 ƒ¯¹(x) = √√√x+9 +3 ƒ¯¹(x) = √√x+9 − 3
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