State the formula number, u and du, identify any constants, and show any constant “adjustments” / "Multiply by 1” if needed. Use one of the formulas from the given formula sheet
State the formula number, u and du, identify any constants, and show any constant “adjustments” / "Multiply by 1” if needed. Use one of the formulas from the given formula sheet
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
State the formula number, u and du, identify any constants, and show any constant “adjustments” / "Multiply by 1” if needed. Use one of the formulas from the given formula sheet
Transcribed Image Text:7x²
8(3x-2)³
dx
![3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
1
U
du =
a + bu
U
(a + bu)²
U
S (a + bu) d
12
n #1,2
a
u²
I
u²
(a + bu)²
u²
(a + bu) ³°
n 1, 2, 3
1
du =
-du
-du =
u²
(a + bujn du =
1₁
1₁
du
1
u (a + bu)
1₁
-du
1
u(a + bu)²
1
·(bu - a In |a + bu) + C
6²
-du
1
u²(a + bu)
-du
1
u²(a + bu)²
-du
1
6²
b²
63
du
-1
[(₁-2)
(n-2)(a + bu)-2
bu
a
a + bu
a
bu
1 2a
6³ a + bu
1
= [(₁-3)
b³
(n
a
(2a − bu) + a² In |a + bu + C
+ bu] ·
26
In
a + bu
1
===
+In a + bu + C
- brel) + C
a²
a + bu
a
-1
- 3)(a + bu)"-3
(1/
1
a + bu a
+
a²
2(a + bu)²
1
+ -In
b
+C
-In
a
+
2a ln a + bu + C
a + 2bu
u (a + bu)
U
+
(n-1)(a + bu)"-
a + bu
U
a + bu
+ In a + bu + C
bul] +
buj-1] 40
=)) +
2a
(n-2)(a + bu)-2 (n-1)(a.
+C
+C
1
26
U
- e4] +
+=ln
20
aª
a a + bu
+C,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5827c1a5-5bd0-4404-9166-5246848437fc%2F05c612e1-aef2-48e8-aed1-5e181edc6d0b%2Fdddkpk_processed.png&w=3840&q=75)
Transcribed Image Text:3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
1
U
du =
a + bu
U
(a + bu)²
U
S (a + bu) d
12
n #1,2
a
u²
I
u²
(a + bu)²
u²
(a + bu) ³°
n 1, 2, 3
1
du =
-du
-du =
u²
(a + bujn du =
1₁
1₁
du
1
u (a + bu)
1₁
-du
1
u(a + bu)²
1
·(bu - a In |a + bu) + C
6²
-du
1
u²(a + bu)
-du
1
u²(a + bu)²
-du
1
6²
b²
63
du
-1
[(₁-2)
(n-2)(a + bu)-2
bu
a
a + bu
a
bu
1 2a
6³ a + bu
1
= [(₁-3)
b³
(n
a
(2a − bu) + a² In |a + bu + C
+ bu] ·
26
In
a + bu
1
===
+In a + bu + C
- brel) + C
a²
a + bu
a
-1
- 3)(a + bu)"-3
(1/
1
a + bu a
+
a²
2(a + bu)²
1
+ -In
b
+C
-In
a
+
2a ln a + bu + C
a + 2bu
u (a + bu)
U
+
(n-1)(a + bu)"-
a + bu
U
a + bu
+ In a + bu + C
bul] +
buj-1] 40
=)) +
2a
(n-2)(a + bu)-2 (n-1)(a.
+C
+C
1
26
U
- e4] +
+=ln
20
aª
a a + bu
+C,
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