State the average rate of change of the function f(x) = ax² (a is a constant) in the interval [3, 3+h]. Hence, state the value of a if the instantaneous rate of change is 18.
State the average rate of change of the function f(x) = ax² (a is a constant) in the interval [3, 3+h]. Hence, state the value of a if the instantaneous rate of change is 18.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi, I've just started calculus and I am very confused.
How do you answer question b? It's attached in the second screenshot.
Question 6a is a(6+h) and my working out for question 6b is also attached but it isn't right and I think I've just connected random numbers in random formulas.
Thanks,
![State the average rate of change of the function f(x) = ax² (a is a constant) in the interval
[3,3 + h].
Hence, state the value of a if the instantaneous rate of change is 18.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd03cec43-9b96-4035-a13d-e5d2f7cbfcc1%2Fcbe02fa0-dacb-4f31-b1e5-16bf233fd8f9%2F2jknxx_processed.png&w=3840&q=75)
Transcribed Image Text:State the average rate of change of the function f(x) = ax² (a is a constant) in the interval
[3,3 + h].
Hence, state the value of a if the instantaneous rate of change is 18.

Transcribed Image Text:8:47 pm Fri 7 Jul
< Un'
2(3)a
Ga
b. f(x) = ax² 13₁3th 14-3th-6ax +18 a
f(x) = ax2x
y = 3-5 +6ax-189
= 2009
aug
avy roc= a(6th)
6a+ah
ah = -69
h = -6
y-g₁- m{z-x√√
у-ді
(3-0)
у-(3th)-ба(ос-3)
3th - 6900 + 18a
................
9-3th
A
("
у=3--6+ бах-18а
4= атвах -189
18= 692-189 +9
0=600-18a - 9
3(290c-6a-3)
C
41%
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