STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 4 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920 We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate ? by giving a 98% confidence interval. SOLVE: Find the sample mean ?¯ . (Enter your answer rounded to the nearest whole number.) ?¯= Give a 98% confidence interval, [???,ℎ??ℎ] , for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) ???= ℎ??ℎ=
Unitary Method
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STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 4 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise.
| 33,190 | 31,860 | 32,590 | 26,520 | 33,280 |
| 32,320 | 33,020 | 32,030 | 30,460 | 32,700 |
| 23,040 | 30,930 | 32,720 | 33,650 | 32,340 |
| 24,050 | 30,170 | 31,300 | 28,730 | 31,920 |
We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a
PLAN: We will estimate ? by giving a 98% confidence interval.
SOLVE: Find the sample mean ?¯ . (Enter your answer rounded to the nearest whole number.)
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