State A: - 6x + y = 11,600 State B: 141x+y=7,000 where x = 0 corresponds to the year 2000 and y is in thousands. In what year do the two states have the same population? The two states will have the same population in the year.
State A: - 6x + y = 11,600 State B: 141x+y=7,000 where x = 0 corresponds to the year 2000 and y is in thousands. In what year do the two states have the same population? The two states will have the same population in the year.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![According to projections through the year 2030, the population \( y \) of the given state in year \( x \) is approximated by:
\[
\text{State A:} \quad -6x + y = 11,600
\]
\[
\text{State B:} \quad -14x + y = 7,000
\]
where \( x = 0 \) corresponds to the year 2000 and \( y \) is in thousands. In what year do the two states have the same population?
The two states will have the same population in the year \(\_\_\_\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c391909-e4e2-4c58-85bb-5bea7cb900f2%2F7e3a00be-001b-46bc-b54f-ed8d256c4381%2Fx8abrd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:According to projections through the year 2030, the population \( y \) of the given state in year \( x \) is approximated by:
\[
\text{State A:} \quad -6x + y = 11,600
\]
\[
\text{State B:} \quad -14x + y = 7,000
\]
where \( x = 0 \) corresponds to the year 2000 and \( y \) is in thousands. In what year do the two states have the same population?
The two states will have the same population in the year \(\_\_\_\).
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