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Starting with your solution to the previous task, extend the Circle class by implementing the is an example of a so-called "rich comparison" method, which allows two objects to be compared with standard _eq__ ( ) method. This operators (in this case, the == operator) by triggering a special method call (in this case, the _eq_() method). • x == y calls x._eq__(y) Add the following method to your Circle class: • The special Leq_ (self, other) method defines the behaviour of the equality operator. In this case, two circles are considered to be equal to each other if and only if they have exactly the same radius. The method should return True if two circles are equal, and False otherwise. HINT: You will need to use the isinstance() function to check for cases where a non-circle object is passed to the method - in this case, you should return False immediately. Submit the entire class definition in the answer box below. For example: Test Result c1 = Circle(2.5) False c2 = Circle(4) print (c1 == c2) c1 = Circle(2) c2 = Circle(2) print(c1 == c2) True

Starting with your solution to the previous task, extend the Circle class by implementing the is an example of a so-called "rich comparison" method, which allows two objects to be compared with standard _eq__ ( ) method. This operators (in this case, the == operator) by triggering a special method call (in this case, the _eq_() method). • x == y calls x._eq__(y) Add the following method to your Circle class: • The special Leq_ (self, other) method defines the behaviour of the equality operator. In this case, two circles are considered to be equal to each other if and only if they have exactly the same radius. The method should return True if two circles are equal, and False otherwise. HINT: You will need to use the isinstance() function to check for cases where a non-circle object is passed to the method - in this case, you should return False immediately. Submit the entire class definition in the answer box below. For example: Test Result c1 = Circle(2.5) False c2 = Circle(4) print (c1 == c2) c1 = Circle(2) c2 = Circle(2) print(c1 == c2) True

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Python Programming

Starting with your solution to the previous task, extend the Circle class by implementing the_eq__( ) method. This is an example of a so-called "rich comparison" method, which allows two objects to be compared with standard operators (in this case, the == operator) by triggering a special method call (in this case, the_eq_() method). • x == y calls x._eq_(y) Add the following method to your Circle class: • The special eq_ (self, other) method defines the behaviour of the equality operator. In this case, two circles are considered to be equal to each other if and only if they have exactly the same radius. The method should return True if two circles are equal, and False otherwise. HINT: You will need to use the isinstance() function to check for cases where a non-circle object is passed to the method - in this case, you should return False immediately. Submit the entire class definition in the answer box below. For example: Test Result c1 = Circle(2.5) False c2 = Circle(4) print(c1 == c2) c1 = Circle(2) c2 = Circle(2) print(c1 == c2) True
Transcribed Image Text:Starting with your solution to the previous task, extend the Circle class by implementing the_eq__( ) method. This is an example of a so-called "rich comparison" method, which allows two objects to be compared with standard operators (in this case, the == operator) by triggering a special method call (in this case, the_eq_() method). • x == y calls x._eq_(y) Add the following method to your Circle class: • The special eq_ (self, other) method defines the behaviour of the equality operator. In this case, two circles are considered to be equal to each other if and only if they have exactly the same radius. The method should return True if two circles are equal, and False otherwise. HINT: You will need to use the isinstance() function to check for cases where a non-circle object is passed to the method - in this case, you should return False immediately. Submit the entire class definition in the answer box below. For example: Test Result c1 = Circle(2.5) False c2 = Circle(4) print(c1 == c2) c1 = Circle(2) c2 = Circle(2) print(c1 == c2) True
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