Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and E°cell of the following reactions.  Substance ΔΔG°f (kJ/mol) FeO(s) -255.2 H2(g) 0 Fe(s) 0 H2O(l) -237.2 Pb(s) 0 O2(g) 0 H2SO4(aq) -744.5 PbSO4(s) -813.0   Part 1   See Hint See Periodic Table FeO(s)+H2​(g)Fe(s)+H2​O(l)  ΔΔG° =     kJ     Part 2      FeO(s)+H2​(g)Fe(s)+H2​O(l)  E°cell =     V     Part 3     2Pb(s)+O2​(g)+2H2​SO4​(aq)2PbSO4​(s)+2H2​O(l)   ΔΔG° =     kJ     Part 4    2Pb(s)+O2​(g)+2H2​SO4​(aq)2PbSO4​(s)+2H2​O(l)   E°cell =     V

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Chapter18: Thermodynamics And Equilibrium
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Problem 18.43QP: The free energy of formation of one mole of compound refers to a particular chemical equation. For...
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Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and cell of the following reactions.
 
Substance ΔΔG°f (kJ/mol)
FeO(s) -255.2
H2(g) 0
Fe(s) 0
H2O(l) -237.2
Pb(s) 0
O2(g) 0
H2SO4(aq) -744.5
PbSO4(s) -813.0
 

Part 1  

See Hint
See Periodic Table
FeO(s)+H2​(g)Fe(s)+H2​O(l)
 ΔΔG° =     kJ   

 

Part 2   

 
FeO(s)+H2​(g)Fe(s)+H2​O(l)
 E°cell =     V   

 

Part 3  

 
2Pb(s)+O2​(g)+2H2​SO4​(aq)2PbSO4​(s)+2H2​O(l)
  ΔΔG° =     kJ   
 

Part 4   

2Pb(s)+O2​(g)+2H2​SO4​(aq)2PbSO4​(s)+2H2​O(l)
  cell =     V   
 
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