Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and E°cell of the following reactions. Substance ΔΔG°f (kJ/mol) FeO(s) -255.2 H2(g) 0 Fe(s) 0 H2O(l) -237.2 Pb(s) 0 O2(g) 0 H2SO4(aq) -744.5 PbSO4(s) -813.0 Part 1 See Hint See Periodic Table FeO(s)+H2(g)Fe(s)+H2O(l) ΔΔG° = kJ Part 2 FeO(s)+H2(g)Fe(s)+H2O(l) E°cell = V Part 3 2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l) ΔΔG° = kJ Part 4 2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l) E°cell = V
Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and E°cell of the following reactions. Substance ΔΔG°f (kJ/mol) FeO(s) -255.2 H2(g) 0 Fe(s) 0 H2O(l) -237.2 Pb(s) 0 O2(g) 0 H2SO4(aq) -744.5 PbSO4(s) -813.0 Part 1 See Hint See Periodic Table FeO(s)+H2(g)Fe(s)+H2O(l) ΔΔG° = kJ Part 2 FeO(s)+H2(g)Fe(s)+H2O(l) E°cell = V Part 3 2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l) ΔΔG° = kJ Part 4 2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l) E°cell = V
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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.43QP: The free energy of formation of one mole of compound refers to a particular chemical equation. For...
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Question
Starting with the standard free energies of formation from the following table, calculate the values of ΔG° and E°cell of the following reactions.
Substance | ΔΔG°f (kJ/mol) |
FeO(s) | -255.2 |
H2(g) | 0 |
Fe(s) | 0 |
H2O(l) | -237.2 |
Pb(s) | 0 |
O2(g) | 0 |
H2SO4(aq) | -744.5 |
PbSO4(s) | -813.0 |
Part 1
See Hint
See Periodic Table
FeO(s)+H2(g)Fe(s)+H2O(l)
Part 2
FeO(s)+H2(g)Fe(s)+H2O(l)
Part 3
2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l)
Part 4
2Pb(s)+O2(g)+2H2SO4(aq)2PbSO4(s)+2H2O(l)
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