Starting from rest, a 57.0 kg woman jumps down to the floor from a height of 0.800 m, and immediately jumps back up into the air. While she is in contact with the ground during the time interval 0 < t< 0.800 s, the force she exerts on the floor can be modeled using the function F= 9,200t - 11,500t2 where F is in newtons and t is in seconds. (a) What impulse (in N- s) did the woman receive from the floor? (Enter the magnitude. Round your answer to at least three significant figures.) 981 V N.s (b) With what speed (in m/s) did she reach the floor? (Round your answer to at least three significant figures.) 3.96 V m/s (c) With what speed (in m/s) did she leave it? (Round your answer to at least three significant figures.) Apply the impulse-momentum equation, and solve for the final velocity. Note that both gravity and the floor impart the impulse to the woman, so both terms need to be included in your equation. m/s 212 (d) To what height (in m) did she jump upon leaving the floor?

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
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second time sending as the answer is wrong and can you answer the last part

Starting from rest, a 57.0 kg woman jumps down to the floor from a height of 0.800 m, and immediately jumps back up into the air. While she is in contact with the ground during the time interval 0 <t < 0.800 s,
the force she exerts on the floor can be modeled using the function
F = 9,200t – 11,500t2
where F is in newtons andt is in seconds.
(a) What impulse (in N· s) did the woman receive from the floor? (Enter the magnitude. Round your answer to at least three significant figures.)
981
N:s
(b) With what speed (in m/s) did she reach the floor? (Round your answer to at least three significant figures.)
3.96
m/s
(c) With what speed (in m/s) did she leave it? (Round your answer to at least three significant figures.)
21.2
Apply the impulse-momentum equation, and solve for the final velocity. Note that both gravity and the floor impart the impulse to the woman, so both terms need to be included in your equation. m/s
(d) To what height (in m) did she jump upon leaving the floor?
m
Transcribed Image Text:Starting from rest, a 57.0 kg woman jumps down to the floor from a height of 0.800 m, and immediately jumps back up into the air. While she is in contact with the ground during the time interval 0 <t < 0.800 s, the force she exerts on the floor can be modeled using the function F = 9,200t – 11,500t2 where F is in newtons andt is in seconds. (a) What impulse (in N· s) did the woman receive from the floor? (Enter the magnitude. Round your answer to at least three significant figures.) 981 N:s (b) With what speed (in m/s) did she reach the floor? (Round your answer to at least three significant figures.) 3.96 m/s (c) With what speed (in m/s) did she leave it? (Round your answer to at least three significant figures.) 21.2 Apply the impulse-momentum equation, and solve for the final velocity. Note that both gravity and the floor impart the impulse to the woman, so both terms need to be included in your equation. m/s (d) To what height (in m) did she jump upon leaving the floor? m
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