Standing at the base of one of the cliffs cof Mt. Arapiles in Victoria, Australia, a hiker hears a rock break loose from a height of 125.0 m. He can't see the rock right away, but then does, 2.50 s later. (a) How far above the hiker is the rock when he can see it? (b) How much time does he have to move before the rock hits his head?
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- A soccer player kicks a rock horizontally off a 35.0-m-high cliff into a pool of water. If the player hears the sound of the splash 2.82 s later, what was the initial speed given to the rock? Assume the speed of sound in air is 343 m/s.A particle moving along the xx-axis has its position described by the function x=(5t4+6t2+2t+5)m, where t is in s.At t = 12 s, what is the particle's position?The human circulatory system is closed - that is, the blood pumped out of the left ventricle of the heart into the arteries is constrained to a series of continuous, branching vessels as it passes through the capillaries and then into the veins as it returns to the heart. The blood in each of the hearts four chambers comes briefly to rest before it is ejected by contraction of the heart muscle. The contraction of the left ventricle lasts 250 ms and the speed of blood flow in the aorta (the large artery leaving the heart) is 0.80 m/s at the end of the contraction.
- A particle travels so that its acceleration is given by 2e-ti + 5 cos tj 3 sin t k a If the particle is located at (1, –3, 2) at time t=0 and is moving with a velocity given by 4i - 3j+ 2k, find the velocity at any time t>0. a) (6 - 2e*)i +(5 sint - 3)j +(3cost)k b) (6-2e*)i +(5 sint-3)j +(3cost-1)k c) (6 + 2e*)i +(5 sint + 3)j +(3cost)k d) (6 - 2e*)i +(5 sint +1)j +(3cost)kDuring a 4.75 s interval, a particle's coordinates change from x = 11.0 m, y = 5.25 m to x = 30.3 m, y = -5.25 m. Assuming the particle's velocity is constant, what will its coordinates be at the end of the next 4.75 s interval?The motion of a particle is described by 15cm and the equation x = a + bt| where a = b = 3cm. Its instantaneous velocity at time 3 sec will be
- A dog sees a squirrel 7.4 m away. The dog runs towards the squirrel at 6.2 m/s. The squirrel was not paying attention and didn’t notice the dog until the dog was only 2.4 m away. If the tree is 11.47 m away from the squirrel (in the opposite direction of the dog), what is the minimum speed the squirrel will need to run at to get away(ie get to the tree at least at the same time as the dog)?An accelerating Cheetah reaches a velocity of 25 m/s in 4.5s after which it immediately begins to slow down. What is its acceleration and what is its effective striking range (ie., what distance does it cover)?A bird is flying due east, its distance from a tall building is given by x(t)= 32.0 + (11.1 m/s)t - (0.0350)t^3 what is the instantenous velocity when t=8.00? i have tried this and have gotten 8.86 in which the program tells me that is incorrect...
- The Sultan Qaboos road is designed to operate at a speed of 100Kmph, but some people are racing above the limit and some people are trailing below 80Kmph, and cause multiple incidents on road. Design a radar frequency so that detect the both the speeds that is below 70kmph, and above 110kmph, provided the PRF is 500Hz only. The radar should not be blind between the above specified velocities and it should detect both the speed accurately.(Explain your assumptions of the radar and their specifications clearly, so that which radar frequency can be readily used on site)A girl lays on the edge of a cliff and looks down at the water below. Wondering how far the drop is, she drops a pebble over the edge and counts 2.75 s from the time that she releases the pebble (from rest) to when it strikes the water. How far below the cliff is the surface of the water? (Use g = 9.80 m/s2 as the acceleration of gravity.)The position, x, of a longboarder as a function of time, t, is given by x = (-3.22 m/s)t + (7.0 m) At a time of 5.6 s, what is the displacement of the longboarder from the initial position?