Standards and their Preparation The set of standards are often prepared by quantitative dilution of a solution of known concentration. The dilution factor is the number by which you must multiply the original concentration to find the concentration of the diluted solution. The dilution factor is calculated as below. dilution factor = concentration of diluted concentration of original As an example, if the original solution is 2 mol L-1 sugar, and the final solution is 1 mol L-1 sugar the dilution factor is 0.5. The dilution factor is also equal to the ratio of the volumes of the original and diluted solutions. Because the diluted solution has a larger volume, it is now in the denominator. dilution factor = volume of original volume of diluted Because the diluted solution has a larger volume, it is in the denominator. Thus if 10 mL of water is added to 10 mL of 2 mol L-1 sugar, the final volume is 20 mL. By the ratio of the volumes, the dilution factor is 0.5. Using this and the original concentration, the concentration of the diluted solution is 1 mol L-1 sugar. In the exercise below, concentrations are expressed as percentages. i. A 40% standard solution of ethanol in water is used in preparing a 10% ethanol solution. Choose the dilution factor in this case. [Select] ii. 25 mL of the 40% ethanol solution is used to prepare the 10% ethanol. What is the final volume of the solution? [Select] iii. How much water must be added to do the dilution? [Select] ✓ mL iv. In another experiment, 120 mL of water is added to 30 mL of the 40% ethanol solution. a. Choose the dilution factor. [Select] b. Choose the concentration of the diluted solution. [Select] %
Standards and their Preparation The set of standards are often prepared by quantitative dilution of a solution of known concentration. The dilution factor is the number by which you must multiply the original concentration to find the concentration of the diluted solution. The dilution factor is calculated as below. dilution factor = concentration of diluted concentration of original As an example, if the original solution is 2 mol L-1 sugar, and the final solution is 1 mol L-1 sugar the dilution factor is 0.5. The dilution factor is also equal to the ratio of the volumes of the original and diluted solutions. Because the diluted solution has a larger volume, it is now in the denominator. dilution factor = volume of original volume of diluted Because the diluted solution has a larger volume, it is in the denominator. Thus if 10 mL of water is added to 10 mL of 2 mol L-1 sugar, the final volume is 20 mL. By the ratio of the volumes, the dilution factor is 0.5. Using this and the original concentration, the concentration of the diluted solution is 1 mol L-1 sugar. In the exercise below, concentrations are expressed as percentages. i. A 40% standard solution of ethanol in water is used in preparing a 10% ethanol solution. Choose the dilution factor in this case. [Select] ii. 25 mL of the 40% ethanol solution is used to prepare the 10% ethanol. What is the final volume of the solution? [Select] iii. How much water must be added to do the dilution? [Select] ✓ mL iv. In another experiment, 120 mL of water is added to 30 mL of the 40% ethanol solution. a. Choose the dilution factor. [Select] b. Choose the concentration of the diluted solution. [Select] %
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
100%
i:2.5/4.0/0.25/0.4
ii:6.25/75/25/100/50
iii:25/50/75
iv1:4/0.2/0.75/0.25
iv2:8/10/20/30/40
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