standard deviation of the exam scores
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Scores on an exam (out of 100 points) given in a university statistics course are displayed in the provided histogram
- Describes the shape of the distribution of exam scores
- If a score of 15 is added to the data, the
mean will be bigger or smaller than the median? - Based on the histogram, what is likely the standard deviation of the exam scores?
![16
14-
12-
10
8.
6.
4
72
76
80
84
88
92
Exam Scores
Frequency](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F592d0571-18d1-464d-9d59-818798c58f60%2Ff11c2aaf-fdf7-4db1-a2e2-4c476bf80069%2Feq0nilr_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Histogram: The frequency distribution shows how the data is distributed.
1)From the Graph, we Observe that the Distribution is symmetric around a mean of 82
therefore it indicates that mean=mode =median=82
2) If a score of 15 is added then the mean is greater than the median
because we know the relation if Distribution is Positively skewed then mean>median>mode
therefore here Mean>Median
3) we have to find a standard deviation from histogram for values 72,74,76,78,80,82,84,86,88,90,92
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