# stack the following list vertically with ones matrix and transpose it mat = [1, 5, 3, 7, 8] [[1. 1.] [5. 1.] [3. 1.] [7. 1.] [8. 1.]]
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in python using google collab
![# stack the following list vertically with ones matrix and transpose it
mat =
[1, 5, 3, 7, 8]
[[1. 1.]
[5. 1.]
[3. 1.]
[7. 1.]
[8. 1.]]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff28916f9-56ea-416a-a2ff-02095e672032%2F8ae6073e-5e29-42ad-bc06-ce35bfa50ef8%2Fsvtwzro_processed.png&w=3840&q=75)
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- JAVA CODE PLEASE Linked List Practice ll by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes. Arrange the nodes in ascending order first before printing them using the printNodes function. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5def large_matrix(matrix: list[list[int]]) -> int:"""Returns the area of the rectangle in the area of a rectangle is defined by number of 1's that it contains.The matrix will only contain the integers 1 and 0.>>> case = [[1, 0, 1, 0, 0],... [1, 0, 1, 1, 1],... [1, 1, 1, 1, 1],... [1, 0, 0, 1, 0]]>>> largest_in_matrix(case1)6"" You must use this helper code: def large_position(matrix: list[list[int]], row: int, col: int) -> int: a = rowb = colmax = 0temp = 0rows = len(matrix)column = len(matrix[a])while a < rows and matrix[a][col] == 1:temp = 0while b < column and matrix[a][b] == 1:temp = temp + 1b = b + 1column = ba = a + 1if (a != row+1):temp2 = temp * (a - row)else:temp2 = tempif max < temp2:max = temp2b = colreturn max """ remember: Please do this on python you should not use any of the following: dictionaries or dictionary methods try-except break and continue statements recursion map / filter import""'def create_matrix(lst): """Create matrix will take matrix represented as a list of list. And output a function which will index the input matrix Args: lst (List of List): A list of list representation of matrix. There will be more than one element of list type in lst. Returns: [function]: An indexing function. >>> matrix_index1 = create_matrix([[1, 2], [2, 3]]) # a 2 x 2 matrix. >>> matrix_index2 = create_matrix([[1, 2, 3], [2, 3, 1]]) # a 2 x 3 matrix. >>> matrix_index3 = create_matrix([[1, 2, 3], []]) # an invalid matrix """ ### Modify your code here def matrix_index(i=None, j=None): """Indexing function which will retrive (i, j) entry of the input matrix representation Args: i (int, optional): row index. Defaults to None. (0-index) j (int, optional): column index. Defaults to None. (0-index) Return: List of List: a…
- P5:Given the following singly linked list: s->m->h->t->y->h->r If you run the following function, then print out the linked list, what do you get? void SLL::f3() ( SNode *tmp; SNode *tmp2 - first; // holds the address of "s" while (tmp2->next !- NULL) { tmp = tmp2->next; tmp2->next = tmp2->next->next; tmp->next = first; first = tmp; last = tmp2;JAVA CODE PLEASE Linked List Practice l by CodeChum Admin Write a function printNodes that takes in the head of a linked list and prints all the values of that linked list using a while loop. Print the values separated by a [space]->[space] In the main function, write a program that asks the user to input five integers and assign these values to the nodes then print the five nodes using the printNodes function. An initial code is provided for you. Just fill in the blanks. Input 1. One line containing an integer 2. One line containing an integer 3. One line containing an integer 4. One line containing an integer 5. One line containing an integer Output Enter·number·1:·1 Enter·number·2:·2 Enter·number·3:·3 Enter·number·4:·4 Enter·number·5:·5 1·->·2·->·3·->·4·->·5How is an array stored in main memory? How is a linked list stored in main memory? What are their comparative advantages and disadvantages? Give examples of data that would be best stored as an array and as a linked list.
- Question 1a: Write an algorithm / program that accept ten values and store them in an array in sorted order. 1B: Write a program that implements stack and queue by using array and link list.def small_index(items: list[int]) -> int:"""Return the index of the first integer in items that is less than its index,or -1 if no such integer exists in items.>>> small_index([2, 5, 7, 99, 6])-1>>> small_index([-5, 8, 9, 16])0>>> small_index([5, 8, 9, 0, 1, 3])3"""Solve the following Program Using C++ solve it correctly and quickly please.
- Pythondef create_matrix(lst): """Create matrix will take matrix represented as a list of list. And output a function which will index the input matrix Not allowed to Import Libraries Args: lst (List of List): A list of list representation of matrix. There will be more than one element of list type in lst. Returns: [function]: An indexing function. >>> matrix_index1 = create_matrix([[1, 2], [2, 3]]) # a 2 x 2 matrix. >>> matrix_index2 = create_matrix([[1, 2, 3], [2, 3, 1]]) # a 2 x 3 matrix. >>> matrix_index3 = create_matrix([[1, 2, 3], []]) # an invalid matrix """ ### Modify your code here def matrix_index(i=None, j=None): """Indexing function which will retrive (i, j) entry of the input matrix representation Args: i (int, optional): row index. Defaults to None. (0-index) j (int, optional): column index. Defaults to None. (0-index)…Q) Give as much differences as you can between a linked list and a stack.
