ssume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: ) P(-z< Z < z) = 0.95. = 1.96 (Round the answer to 2 decimal places.) -) P(-z< Z < z) = 0.99. = 2.576 (Round the answer to 2 decimal places.) P(-z < Z < z) = 0.66. = ) P(-z< Z < z) = 0.9973. (Round the answer to 2 decimal places.) (Round the answer to 1 decimal place.)
ssume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: ) P(-z< Z < z) = 0.95. = 1.96 (Round the answer to 2 decimal places.) -) P(-z< Z < z) = 0.99. = 2.576 (Round the answer to 2 decimal places.) P(-z < Z < z) = 0.66. = ) P(-z< Z < z) = 0.9973. (Round the answer to 2 decimal places.) (Round the answer to 1 decimal place.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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 to determine the value for \( z \) that solves each of the following:
1. \( P(-z < Z < z) = 0.95 \)
- Solution:
\[
z = 1.96 \quad \text{(Round the answer to 2 decimal places.)}
\]
2. \( P(-z < Z < z) = 0.99 \)
- Solution:
\[
z = 2.576 \quad \text{(Round the answer to 2 decimal places.)}
\]
3. \( P(-z < Z < z) = 0.66 \)
- Solution:
\[
z = \quad \text{(Round the answer to 2 decimal places.)}
\]
4. \( P(-z < Z < z) = 0.9973 \)
- Solution:
\[
z = \quad \text{(Round the answer to 1 decimal place.)}
\]
*For problems (c) and (d), students are expected to use Appendix Table III to fill in the values of \( z \) that correspond to the provided probabilities.*
This exercise aims to help students understand how to use the standard normal distribution table to find critical Z values, a crucial skill in statistics for hypothesis testing and confidence interval estimation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbb0b53a-c5e9-4f61-9041-8945e4ef01cb%2Fc581aad7-4e3f-4db8-b4f8-5c79d7687c52%2Fb32l9ma_processed.png&w=3840&q=75)
Transcribed Image Text:**Using Appendix Table III to Determine Z Values for Standard Normal Distribution**
Assume \( Z \) has a standard normal distribution. Use [Appendix Table III](URL link) to determine the value for \( z \) that solves each of the following:
1. \( P(-z < Z < z) = 0.95 \)
- Solution:
\[
z = 1.96 \quad \text{(Round the answer to 2 decimal places.)}
\]
2. \( P(-z < Z < z) = 0.99 \)
- Solution:
\[
z = 2.576 \quad \text{(Round the answer to 2 decimal places.)}
\]
3. \( P(-z < Z < z) = 0.66 \)
- Solution:
\[
z = \quad \text{(Round the answer to 2 decimal places.)}
\]
4. \( P(-z < Z < z) = 0.9973 \)
- Solution:
\[
z = \quad \text{(Round the answer to 1 decimal place.)}
\]
*For problems (c) and (d), students are expected to use Appendix Table III to fill in the values of \( z \) that correspond to the provided probabilities.*
This exercise aims to help students understand how to use the standard normal distribution table to find critical Z values, a crucial skill in statistics for hypothesis testing and confidence interval estimation.
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