ssume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: ) P(-z< Z < z) = 0.95. = 1.96 (Round the answer to 2 decimal places.) -) P(-z< Z < z) = 0.99. = 2.576 (Round the answer to 2 decimal places.) P(-z < Z < z) = 0.66. = ) P(-z< Z < z) = 0.9973. (Round the answer to 2 decimal places.) (Round the answer to 1 decimal place.)

MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
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**Using Appendix Table III to Determine Z Values for Standard Normal Distribution**

Assume \( Z \) has a standard normal distribution. Use [Appendix Table III](URL link) to determine the value for \( z \) that solves each of the following:

1. \( P(-z < Z < z) = 0.95 \)
    - Solution:
    \[
    z = 1.96 \quad \text{(Round the answer to 2 decimal places.)}
    \]

2. \( P(-z < Z < z) = 0.99 \)
    - Solution:
    \[
    z = 2.576 \quad \text{(Round the answer to 2 decimal places.)}
    \]

3. \( P(-z < Z < z) = 0.66 \)
    - Solution:
    \[
    z = \quad \text{(Round the answer to 2 decimal places.)}
    \]

4. \( P(-z < Z < z) = 0.9973 \)
    - Solution:
    \[
    z = \quad \text{(Round the answer to 1 decimal place.)}
    \]

*For problems (c) and (d), students are expected to use Appendix Table III to fill in the values of \( z \) that correspond to the provided probabilities.*

This exercise aims to help students understand how to use the standard normal distribution table to find critical Z values, a crucial skill in statistics for hypothesis testing and confidence interval estimation.
Transcribed Image Text:**Using Appendix Table III to Determine Z Values for Standard Normal Distribution** Assume \( Z \) has a standard normal distribution. Use [Appendix Table III](URL link) to determine the value for \( z \) that solves each of the following: 1. \( P(-z < Z < z) = 0.95 \) - Solution: \[ z = 1.96 \quad \text{(Round the answer to 2 decimal places.)} \] 2. \( P(-z < Z < z) = 0.99 \) - Solution: \[ z = 2.576 \quad \text{(Round the answer to 2 decimal places.)} \] 3. \( P(-z < Z < z) = 0.66 \) - Solution: \[ z = \quad \text{(Round the answer to 2 decimal places.)} \] 4. \( P(-z < Z < z) = 0.9973 \) - Solution: \[ z = \quad \text{(Round the answer to 1 decimal place.)} \] *For problems (c) and (d), students are expected to use Appendix Table III to fill in the values of \( z \) that correspond to the provided probabilities.* This exercise aims to help students understand how to use the standard normal distribution table to find critical Z values, a crucial skill in statistics for hypothesis testing and confidence interval estimation.
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