ssume you have an unlimited supply of O2. CH4 (g) + 2 O₂ (g) – CO₂ (g) + 2 H₂O (g)

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For the combustion of methane reaction, how many moles of H₂O can be produced from 1.30 moles of methane (CH₄)? Assume you have an unlimited supply of O₂.

\[ \text{CH}_4 (g) + 2 \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \text{H}_2\text{O} (g) \]

**Explanation of the Chemical Equation:**
The balanced chemical equation depicts the combustion of methane. 

- **Reactants:**
  - Methane (\(\text{CH}_4\)) in the gaseous state.
  - Oxygen (\(\text{O}_2\)) in the gaseous state, with a stoichiometric coefficient of 2, indicating that two moles of oxygen react with one mole of methane.

- **Products:**
  - Carbon dioxide (\(\text{CO}_2\)) in the gaseous state, produced in a 1:1 ratio with methane.
  - Water (\(\text{H}_2\text{O}\)) in the gaseous state, with a stoichiometric coefficient of 2, indicating that two moles of water are formed per mole of methane reacted.

**Calculation:**
According to the balanced equation, 1 mole of methane produces 2 moles of water. Therefore, 1.30 moles of methane will produce:

\[ 1.30 \, \text{moles CH}_4 \times \frac{2 \, \text{moles H}_2\text{O}}{1 \, \text{mole CH}_4} = 2.60 \, \text{moles H}_2\text{O} \]
Transcribed Image Text:For the combustion of methane reaction, how many moles of H₂O can be produced from 1.30 moles of methane (CH₄)? Assume you have an unlimited supply of O₂. \[ \text{CH}_4 (g) + 2 \text{O}_2 (g) \rightarrow \text{CO}_2 (g) + 2 \text{H}_2\text{O} (g) \] **Explanation of the Chemical Equation:** The balanced chemical equation depicts the combustion of methane. - **Reactants:** - Methane (\(\text{CH}_4\)) in the gaseous state. - Oxygen (\(\text{O}_2\)) in the gaseous state, with a stoichiometric coefficient of 2, indicating that two moles of oxygen react with one mole of methane. - **Products:** - Carbon dioxide (\(\text{CO}_2\)) in the gaseous state, produced in a 1:1 ratio with methane. - Water (\(\text{H}_2\text{O}\)) in the gaseous state, with a stoichiometric coefficient of 2, indicating that two moles of water are formed per mole of methane reacted. **Calculation:** According to the balanced equation, 1 mole of methane produces 2 moles of water. Therefore, 1.30 moles of methane will produce: \[ 1.30 \, \text{moles CH}_4 \times \frac{2 \, \text{moles H}_2\text{O}}{1 \, \text{mole CH}_4} = 2.60 \, \text{moles H}_2\text{O} \]
Expert Solution
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In combustion reaction of methane one mole of methane react with two mole of oxygen and produced two mole of water and one mole of carbon dioxide 

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