square root Lewis Graham rate 1 rate 2 > mm2 - rate of effusion - fast - mm1 - Thomas Graham - Slow molar mass 2 molar mass 1 Heavier Graham's law of effusion molar mass - lighter - inversely proportional rate 2 rate 1 molar mass 2 molar mass 1 • The Scottish Chemist named (1.) effusion of gases to be known as (2.) the gases pass through a barrier. proposed the law of He explained how • The (3.) • Graham's Law of effusion means that the rate of motion of a gas is (5.) to the (6.) the gas, the (4.) it finds exit. of its molar mass. • The Graham's law of effusion is mathematically expressed as (7.) • When identifying the rate of two different gases, consider the heavier molar mass as the (8.) in the equation. • In the mathematical equation of Graham's Law of Effusion, r1 and r2 are the (9.) (10.) of the two gases and the mm1 and mm2 correspond to their
square root Lewis Graham rate 1 rate 2 > mm2 - rate of effusion - fast - mm1 - Thomas Graham - Slow molar mass 2 molar mass 1 Heavier Graham's law of effusion molar mass - lighter - inversely proportional rate 2 rate 1 molar mass 2 molar mass 1 • The Scottish Chemist named (1.) effusion of gases to be known as (2.) the gases pass through a barrier. proposed the law of He explained how • The (3.) • Graham's Law of effusion means that the rate of motion of a gas is (5.) to the (6.) the gas, the (4.) it finds exit. of its molar mass. • The Graham's law of effusion is mathematically expressed as (7.) • When identifying the rate of two different gases, consider the heavier molar mass as the (8.) in the equation. • In the mathematical equation of Graham's Law of Effusion, r1 and r2 are the (9.) (10.) of the two gases and the mm1 and mm2 correspond to their
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:> mm2
- rate of effusion
- fast
- mm1
- Thomas Graham
- Slow
rate 2
rate 1
square root
Lewis Graham
rate 1
rate 2
molar mass 2
molar mass 1
Heavier
Graham's law of effusion
molar mass
- lighter
- inversely proportional
molar mass 2
molar mass 1
• The Scottish Chemist named (1.)
effusion of gases to be known as (2.)
the gases pass through a barrier.
proposed the law of
He explained how
• The (3.)
• Graham's Law of effusion means that the rate of motion of a gas is (5.)
to the (6.)
the gas, the (4.)
it finds exit.
of its molar mass.
• The Graham's law of effusion is mathematically expressed as (7.)
• When identifying the rate of two different gases, consider the heavier molar mass
as the (8.)
in the equation.
• In the mathematical equation of Graham's Law of Effusion, r1 and r2 are the
(9.)
(10.)
of the two gases and the mm1 and mm2 correspond to their
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