SQU is trying a new particle accelerator design with a mechanical component using a spring thatdoes not obey Hooke's law. When stretched/compressed x metres, it exerts a force of57.6x +72.6x²(a) Compute the work required to stretch the spring from x= 0.6 m to x = 1.3 m.(b) With one end of the spring fixed, a particle of mass 1.2 kg is attached to the other end of the%3Dspring when it is stretched by an amount x = 1.3 m. If the particle is then released from rest, whatis its speed at the instant the stretch in the spring is x = 0.6 m?(c) Is the force exerted by the spring conservative or nonconservative? Explain.

Given information: The force exerted is, Fx=57.6x3+72.6x2

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