SQL   give the algebraic form of these queries:   //agregation select count(enfant_id) as "nombre enfants n'ont pas besoin d’aliment de substitution" from enfant where déjeuner='0';   select nom_ag "nom",prénom_ag "prénom",nb_heure_par_se "heures par semaine",   count(agents_id) "nombre des agents" from agents_entretien group by jour; // union select nom_en, prénom_en,'fils' as fils_ou_parent from enfant union

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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SQL
 

give the algebraic form of these queries:

 

//agregation
select count(enfant_id) as "nombre enfants n'ont pas besoin
d’aliment de substitution" from enfant where déjeuner='0';
 
select nom_ag "nom",prénom_ag "prénom",nb_heure_par_se "heures par semaine",
 
count(agents_id) "nombre des agents" from agents_entretien group by jour;
// union
select nom_en, prénom_en,'fils' as fils_ou_parent from enfant
union
select nom_ac,prénom_ac,'parent' as fils_ou_parent from parent_actual;
select nom_en, prénom_en,'fils' as fils_ou_parent from enfant
where enfant.parent_id='2'
union
select nom_ac,prénom_ac,'parent' as fils_ou_parent from parent_actual
where parent_id='2';
// intersection
select * from agents_entretien
where jour in(select jour from nettoyage)
INTERSECT
select * from agents_entretien
where jour in(select jour from nettoyage);
//division
select * from agents_entretien,nettoyage
where agents_entretien.jour=nettoyage.jour
group by nom_ag having count(*)=(select count(*) from nettoyage);
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