Sphere A is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here m1 = m2 = m = 3.33 kg.(a) The elevator starts from rest and accelerates downward with a= 1.35 m/s2. What are the tensions in the two strings in newtons?T1= ____ NT2= ____ N(b) If the elevator moves upward instead with the same acceleration what will be the tension in the two strings in newtons?T1= _____ NT2= _____ N(c) The maximum tension the two strings can withstand is 95.0 N. What maximum upward acceleration (in m/s2) can the elevator have without having one of the strings break? _____ m/s2 Tm,Tm,

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Description: Sphere A is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here m1 = m2 = m = 3.33 kg.(a) The elevator starts from rest and accelerates downwar

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Sphere A is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here m₁ = m₂ = m = 3.33 kg.

(a) The elevator starts from rest and accelerates downward with

a= 1.35 m/s². What are the tensions in the two strings in newtons?

T₁= ____ N

T₂= ____ N

(b) If the elevator moves upward instead with the same acceleration what will be the tension in the two strings in newtons?

T₁= _____ N

T₂= _____ N

(c) The maximum tension the two strings can withstand is 95.0 N. What maximum upward acceleration (in m/s²) can the elevator have without having one of the strings break?

_____ m/s²

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